A device used to initiate and control a sustained nuclear chain reaction.
Answer:
3.6m
Explanation:
if you are at a building that is 46m above the ground, and the professor is 1.80m, the egg must fall:
46m - 1.80m = 44.2m
the egg must fall for 44.2m to land on the head of the professor.
Now, how many time this takes?
we have to use the following free fall equation:
where 
is the height, 
is the initial velocity, in this case 
. 
is the acceleration of gravity: 
and 
is time, thus:
clearing for time:
we know that the egg has to fall for 44.2m, so 
, and , so we the time is:
Finally, if the professor has a speed of 
, it has to be at a distance:
and t=3.002s:
so the answer is the professor has to be 3.6m far from the building when you release the egg
One very handy electrical formula is
Power dissipated by a resistance = (Voltage)²/(resistance) .
24 kilowatts = (240 v)² / Resistance
Multiply each side by (Resistance):
(Resistance) x (24 kilowatts) = (240 v)²
Divide each side by (24 kilowatts):
Resistance = (240 v)² / (24,000 watts)
Resistance = (57,600 / 24,000) (volt² / volt · Amp)
Resistance = 2.4 (volt/Amp)
Resistance = 2.4 Ohms
Answer:
(a) The magnitude of the electric dipole moment is 1.68 x 10⁻¹⁴ C.m
(b) The difference between the potential energies ΔU, is 4.6704 x 10⁻¹¹ J
Explanation:
Given;
magnitude of charge, q = 2 nC = 2 x 10⁻⁹ C
distance of separation, d = 8.4 μm = 8.4 x 10⁻⁶ m
strength of electric field, E = 1390 N/C
(a) the magnitude of the electric dipole moment
p = qd
p = (2 x 10⁻⁹ C)(8.4 x 10⁻⁶ m)
p = 1.68 x 10⁻¹⁴ C.m
(b) the difference between the potential energies for dipole orientations parallel and anti-parallel to E
ΔU = U(180) - U(0)
ΔU = 2pE
ΔU = 2(1.68 x 10⁻¹⁴ )(1390)
ΔU = 4.6704 x 10⁻¹¹ J
