Answer:
30.66 knots
Explanation:
Distance of ship A from B at noon = 50 NM
= Velocity of ship A = 22 knots = 22 NM/h
= Velocity of ship B = 23 knots = 23 NM/h
Distance travelled by ship A from noon to 3 PM = 22×3 = 66 NM
a = Total distance travelled by ship A = 50+66 = 116 NM
b = Total distance travelled by ship B till 3 PM = 23×3 = 69 NM
c = Distance between Ship A and B at 3 PM = √(116²+69²) = 134.97 NM
a²+b² = c² (Pythagoras theorem)
Now differentiating with respect to time
∴ The velocity with which the distance is changing at 3 PM (3 hours later) is 30.66 knots
Answer:
Distance, S = 130m
Explanation:
Given the following data;
Initial velocity = 2m/s
Final velocity = 28m/s
Acceleration = 3m/s²
To find the distance, we would use the third equation of motion.
V² = U² + 2aS
Substituting into the equation, we have;
28² = 2² + 2*3*S
784 = 4 + 6S
6S = 784 - 4
6S = 780
S = 780/6
Distance, S = 130m
Answer:
velocity = distance / time
distance = speed * time
Distance= 7*3 = 21
V = 21/3
V = 7
Explanation:
Answer:
No, the car will not make it to the top of the hill.
Explanation:
Let ΔX be how long the slope of the hill is, Δx be how far the car will travel along the slope of the hill, Ф be the angle the slope of the hill makes with the horizontal(bottom of the hill), ki be the kinetic energy of the car at the bottom of the hill and vi be the velocity of the car at the bottom of the hill and kf be the kinetic energy of the car when it stop moving at vf.
Since Ф is the angle between the horizontal and the slope, the relationship between the angle and the slope and the height of the hill is given by
sinФ = 12/ΔX
Which gives you the slope as
ΔX = 12/sinФ
Therefore for the car to reach the top of the hill it will have to travel ΔX.
Ignoring friction the total work done is given by
W = ΔK
W = (kf - ki)
Since the car will come to a stop, kf = 0 J
W = -ki
m×g×sinФ×Δx = 1/2×m×vi^2
(9.8)×sinФ×Δx = 1/2×(10)^2
sinФΔx = 5.1
Δx = 5.1/sinФ
ΔX>>Δx Ф ∈ (0° , 90°)
(Note that the maximum angle Ф is 90° because the slope of a hill can never be greater ≥ 90° because that would then mean the car cannot travel uphill.)
Since the car can never travel the distance of the slope, it can never make it to the top of the hill.
Answer:
Around 3.57m/s
Explanation:
p=mv
Let's denote the momentum, mass, and velocity of the car with the subscript 1, and for the truck use 2. After the collision, the combined momentum can be denoted with the subscript 3.
Hope this helps!
