All categories

2 years ago

Who is the founder of pelincilin

Physics

1 answer:

lianna [129]2 years ago

5 0

Answer:

Alexander Fleming

Explanation:

the founder of pelincilin is Alexander Fleming

You might be interested in

Enumerate two ways that you practice to control manage noise pollution

motikmotik

1. Sound insulation at construction sides.
2. Using silencers in automobiles and replacing old noisy machines with new quitter machines or using lubricants

4 0

1 year ago

What are the major features of the human eye and to what are they analogous in a camera?

adelina 88 [10]

Answer:

The human major features with the analogous of camera are mentioned.

Explanation:

There are the following major features of human eye which are analogue with the camera:

Camera will have shutters which controls light entering into it, human eye consists of Diaphragm which also functions same.

Both gives Real & inverted images.

In camera film records image, in eye image is focused on retina and it is converted into electrical impulses.

Pupil and iris acts as aperture of camera.

8 0

3 years ago

What's the possible impact of the fees must fall?

garri49 [273]

This is a complicated question. Please be more specific.

Thank You

5 0

2 years ago

In the form of radioactive decay known as alpha decay, an unstable nucleus emits a helium-atom nucleus, which is called an alpha

Assoli18 [71]

Answer:

$\mathbf{v_a = 4.06 \times 10^7 \ m/s}$

Explanation:

$\text{The missing part of the question is attached below.} \\ \\ \text{ mass m = 4u and charge q = 2e. Suppose a uranium nucleus with 92 protons decays into }$ $\text{into thorium, with 90 protons, and an alpha particle. The alpha particle is initally at rest at }$ $\text{ the surface of the thorium nucleus, which is 15 fm in diameter. What is the speed of the alpha}$ $\text{particle when it is detected in the laboratory? Assume the thorium nucleus remains at rest. }$

$\text{So, from the above infromation;}$

$radius (r) = \dfrac{15 \ fm }{2}$

$radius (r) = 7.5 \times 10^{-15} \ m$

$\text{Using the formula for potential energy}$

$U = \dfrac{(9\times 10^9 \ Nm^2/C^2)(2(1.6\times10^{-19} \ C ))(90)(1.6\times 10^{-19} C)}{7.5 \times 10^{-13} \ m}$

$U = 5.529 \times 10^{-12} \ J$

$\text{Now, the speed of the alpha particle can be estimated from the conservation of energy principle}$ $\dfrac{1}{2}mv_a^2= 5.529 \times 10^{-12} J$

$v_a = \sqrt{\dfrac{2(5.529 \times 10^{-12} \ J)}{4(1.67 \times 106{-37} \ kg)}}$

$\mathbf{v_a = 4.06 \times 10^7 \ m/s}$

4 0

2 years ago

3. The impulse necessary to change the momentum of an object by 5<br> kgm/s is:

shepuryov [24]

Answer:

Impulse, J = 5 kg-m/s

Explanation:

Accoding to impulse-momentum theorem, the change in momentum of an object is equal to the impulse applied to it. In this problem, the change in momentum of an object is 5 kg-m/s.

We need to find the impulse necessary to change the momentum. So, impulse will be equal to 5 kg-m/s.

6 0

2 years ago

Who is the founder of pelincilin​

Who is the founder of pelincilin