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snow_lady [41]
3 years ago
12

Two planets have masses 2 x 10^23 kg and 5 x 10^22 kg, and the distance between them is 3 x 10^16 m. Calculate the gravitational

force between the two planets. (You may round your answer to one decimal place.)
Physics
1 answer:
xxTIMURxx [149]3 years ago
3 0

Explanation:

given,

mass of one planet (m1)=2*10^23 kg

mass of another planet (m2)=5*10^22kg

distance between them(d)=3*10^16m

gravitational constant(G)=6.67*10^-11Nm^2kg^-2

gravitational force between them(F)=?

we know,

F=Gm1m2/d^2

or, F=6.67*10^-11*2*10^23*5*10^22/(3*10^16)^2

or, F=6.67*2*5*10^-11+23+22/3*3*10^32

or, F=66.7*10^34/9*10^32

or, F=7.41*10^34-32

•°• F=7.41*10^2

thus, the gravitational force between them is 7.14*10^2

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Kieran takes off from rest down a 50 m high, 10° slope on his jet-powered skis. The skis have a thrust of 280 N parallel to the
xz_007 [3.2K]

Answer:0.46

Explanation:

Given

Initial height h=50 m

inclination \theta =10^{\circ}

Thrust=280 N

combined mass of kieran and skis m=50 kg

Speed at the bottom v=40 m/s

From Work Energy Theorem

Work done by all the force is equal to change in kinetic Energy

W_{gravity}+W_{friction}+W_{thrust}=\frac{1}{2}mv^2-0------------1

distance traveled along the slope x=\frac{50}{\sin 10}=287.93 m

W_{gravity}=mgh=50\times 9.8\times 50=24500 J

W_{thrust}=F\times x=280\times 287.93=80,620.4 J

W_{friction}=-\mu mg\cos 10

substitute in 1

24,500+80,620.4+W_{friction}=\frac{1}{2}\times 50\times 1600

W_{friction}=40,000-24,500-80,620.4

-\mu \cdot 50\times 9.8\times 287.93=-65,120.4

\mu =\frac{65,120.4}{141,085.7}=0.46

8 0
3 years ago
A sample contains 16 g of a radioactive isotope. how much radioactive
mafiozo [28]

After one half-life, 8 g of radioactive isotope will remain in the sample.

<h3>What is radioactivity?</h3>

The act of producing radiation spontaneously is known as radioactivity. This is accomplished by an unstable atomic nucleus that want to give up some energy in order to move to a more stable form.

The following formula is used to compute the number of half lives elapsed:

\rm N=\frac{N_0}{2^n} \\\\ N=\frac{16}{2} \\\\ N= 8 \ gram

Hence,8 gram of radioactive isotope remains in the sample after 1 half-life.

To learn more about the radioactivity, refer  to the link;

brainly.com/question/1770619

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7 0
2 years ago
Read 2 more answers
Who created earthquake proof buildings?
klemol [59]

Answer:

Japanese created earthquake proof buildings

Explanation:

Countries like Japan where earthquakes are regular. So these important factors are downgraded to nice -to-haves behind the need of Japan structural stability. The Pacific ring of Fire and all its seismic activities are contributed to Japans strict building codes for skyscrapers and Towers. Building codes means, earthquakes proof structures are intended to withstand the earthquake.The prime example of an earthquake-ready country is Japan with its dedication to structural stability.

5 great examples are

1. Mori Tower

2. Tokyo Skytree

3.  Ark Hills Sengokuyama

4.fa-bo

5. Television House

8 0
3 years ago
The resistivity of gold is 2.44 x 10-8 ohms.m at room temperature. A gold wire that is 0.9 mm in diameter and 14 cm long carries
harkovskaia [24]

Answer:

E=0.036 V/m

Explanation:

Given that

Resistivity ,ρ=2.44 x 10⁻⁸ ohms.m

d= 0.9 mm

L= 14 cm

I = 940 m A = 0.94 A

We know that electric field E

E= V/L

V= I R

R=ρL/A

So we can say that

E= ρI/A

Now by putting the values

E=\dfrac{ 2.44\times 10^{-8}\times 0.94}{\dfrac{\pi}{4}(0.9\times 10^{-3})^2}

E=0.036 V/m

6 0
3 years ago
Energy is the energy an object has because it is in motion. *
Mrrafil [7]

The energy an object has due to its motion is called kinetic energy.

3 0
2 years ago
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