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Vaselesa [24]
3 years ago
11

1) Find the current through each resistor PLEASE HELP!

Physics
1 answer:
Alex3 years ago
7 0

Answer:

3 Amperes

Explanation:

This is an example of a parallel and series resistor. The first set of resistors are in parallel(the 6 and 3 ohms).

The total resistance of these two resistors can be solved through the following formula:

\frac{1}{R_{2} } +\frac{1}{R_{3} } =\frac{1}{R_{Equal} }

*This is for any resistors in parallel

Plugging in the numbers, we find that an equivalent resistor has a resistance of 2 ohms. Adding this to the 4 ohms, we get that there a total of 6 ohms of resistance with the resistors in this circuit.

Using Ohms law:

I = V/R

I = 18 V/ 6 Ohms

I = 3 Amperes.

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4 years ago
A coil of wire containing N turns is in an external magnetic field that is perpendicular to the plane of the coil and it steadil
krok68 [10]

Answer:

The Resultant Induced Emf in coil is 4∈.

Explanation:

Given that,

A coil of wire containing having N turns in an External magnetic Field that is perpendicular to the plane of the coil which is steadily changing. An Emf (∈) is induced in the coil.

To find :-

find the induced Emf if rate of change of the magnetic field and the number of turns in the coil are Doubled (but nothing else changes).

So,

   Emf induced in the coil represented by formula

                          ∈  =   -N\frac{d\phi}{dt}                                  ...................(1)

                                          Where:

                                                    .   \phi = BAcos\theta     { B is magnetic field }

                                                                                 {A is cross-sectional area}

                                                    .  N = No. of turns in coil.

                                                    .  \frac{d\phi}{dt} = Rate change of induced Emf.

Here,

Considering the case :-

                                    N1 = 2N  &      \frac{d\phi1}{dt} = 2\frac{d\phi}{dt}

Putting these value in the equation (1) and finding the  new emf induced (∈1)

                           

                                      ∈1 =-N1\times\frac{d\phi1}{dt}

                                      ∈1 =-2N\times2\frac{d\phi}{dt}

                                       ∈1 =4 [-N\times\frac{d\phi}{dt}]

                                        ∈1 = 4∈             ...............{from Equation (1)}      

Hence,

The Resultant Induced Emf in coil is 4∈.        

                           

8 0
4 years ago
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