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ollegr [7]
3 years ago
10

Un avión tarda en llegar a su destino 12 horas. Si recorrió una distancia de 10.700 kilómetros. Calcular su velocidad y expesarl

a en Km/h y en m/s
Physics
1 answer:
elixir [45]3 years ago
5 0

Given that,

Distance, d = 10700 km

Time taken by the airplane to complete the destination, t = 12 hours

We need to find the speed of the airplane. It is equal to the total distance covered divided by total time taken. So,

v=\dfrac{d}{t}\\\\v=\dfrac{10700\ km}{12\ h}\\\\v=891.66\ km/h

We know that,

1 km = 1000 m

1 h = 3600 s

So,

v=891.66\ km/h =\dfrac{891.66\times 1000\ m}{3600\ s}\\\\v=247.68\ m/s

So, the speed of the airplane is 891.66 km/h or 247.68 m/s.

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A 50 W light bulb is plugged into a standard
wolverine [178]

Answer:

$1.26

Explanation:

Power =energy/ time

energy =powerxtime

energy =50x31x24=37200

=37.2kwh

1kwh =3.39

37.2kwh=3.39x37.2=126.108cent

=$1.26

8 0
3 years ago
9. A child standing on a bus remains still when the bus is at rest. When the bus moves forward and then slows down, the child co
marin [14]
I think the answer is C
3 0
4 years ago
Recall that the volume V of a sphere of radius r can be computed using the formula. If the radius of a spherical balloon is incr
alekssr [168]

Answer:

Explanation:

Given that,

A sphere has a volume of V and a radius r

Volume of sphere cam be determine using the formula

V = 4/3 πr³

V = 4πr³ / 3.

If the radius of the sphere is increasing by

dr / dt = 5cm / min

How fast is the volume increasing when r = 10cm

dV / dt =?

From V = 4πr³ / 3

We can calculate dV/dr

dV/dr = 12πr² / 3

dV/dr = 4πr²

Then,

We want to find dV/dt

Using chain rule

dV/dt = dV/dr × dr / dt

dV/dt = 4πr² × 5

dV/dt = 20πr²

So, at r = 10

dV/dt { 20π × 10²

dV/dt = 6283.19 cm/min

The rate at which the volume increase is 6283.19 cm/min

6 0
4 years ago
A diver can change his rotational inertia by drawing his arms andlegs close to his body in the tuck position. After he leaves th
NeX [460]

Answer:

3.14946 rad/s

Explanation:

I_i = Intial moment of inertia

I_f = Final moment of inertia

\omega_i = Initial angular velocity

\omega_f = Final angular velocity = \dfrac{2}{1.33}\times 2\pi\ rad/s

\dfrac{I_f}{I_i}=\dfrac{1}{3}

In this system the angular momentum is conserved

L_i=L_f\\\Rightarrow I_i\omega_i=I_f\omega_f\\\Rightarrow \omega_i=\dfrac{I_f\omega_f}{I_i}\\\Rightarrow \omega_i=\dfrac{1\times \dfrac{2}{1.33}\times 2\pi}{3}\\\Rightarrow \omega_i=3.14946\ rad/s

The angular velocity when the diver left the board is 3.14946 rad/s

3 0
3 years ago
Find the net work W done on the particle by the external forces during the motion of the particle in terms of the initial and fi
steposvetlana [31]

Answer:

W=K_f-K_i

Explanation:

The work done on a particle by external forces is defined as:

W=\int\limits^{r_f}_{r_i} {F\cdot dr} \,

According to Newton's second law F=ma. Thus:

W=\int\limits^{r_f}_{r_i}{ma\cdot dr} \,\\

Acceleration is defined as the derivative of the speed with respect to time:

W=m\int\limits^{r_f}_{r_i}{\frac{dv}{dt}\cdot dr} \,\\\\W=m\int\limits^{r_f}_{r_i}{dv \cdot \frac{dr}{dt}} \,

Speed is defined as the derivative of the position with respect to time:

W=m\int\limits^{v_f}_{v_i} v \cdot dv \,

Kinetic energy is defined as K=\frac{mv^2}{2}:

W=m\frac{v_f^2}{2}-m\frac{v_i^2}{2}\\W=K_f-K_i

3 0
3 years ago
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