The magnitude of the force on the left-hand pole of the thin flexible gold chain of uniform linear density with a mass of 17.1 and, hangs between two 30.0 cm long vertical sticks, which are a distance of 30.0 cm apart will be, 0.167N.
To find the correct answer, we have to know more about the Basic forces that acts upon a body.
<h3>What is force and which are the basic forces that acts upon a body?</h3>
- A push or a pull which changes or tends to change the state or rest, or motion of a body is called Force.
- Force is a polar vector as it has a point of application.
- Positive force represents repulsion and the negative force represented attraction.
- There are 3 main forces acting on a body, such as, weight mg, normal reaction N, and the Tension or pulling force.
<h3>How to solve the problem?</h3>
- We have given that, the gold chain hangs between the vertical sticks of 30cm and the horizontal distance between then is 30cm.
- From the given data, we can find the angle (in the free body diagram, it is given as θ).
- From the free body diagram given, we can write the balanced equations of total force along y direction as,
- From the free body diagram given, we can write the balanced equations of total force along x direction as,
Thus, we can conclude that, the magnitude of force on the left-hand pole will be 0.167N.
Learn more about the Basic forces that acts upon a body here:
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The Gravitational PE (U) depends on three things: the object’s mass (m), its height (h), and gravitational acceleration (g), which is 9.81 m/s^2 on Earth’s surface.
so U = mgh = 9.81mh on earth
mass of the car = 50.0 grams = 0.05kg
height, h:
Hill 1 = 90.0 cm = 0.9m,
Hill 2 = 65.0 cm = 0.65m,
Hill 3 = 20.0 cm = 0.2m
substitute into eqn U = mgh
U @ top of Hill 1 = 0.05*9.81*0.9 = 0.4415J
U @ top of Hill 2 = 0.05*9.81*0.65 = 0.3188J
U @ top of Hill 3 = 0.05*9.81*0.2 = 0.0981J
difference in Gravitational Potential Energy from the top of Hill 1 to the top of Hill 3 = 0.4415 - 0.0981
= 0.3434J where J is the unit for energy, Joules
Answer:
a) 29.36 m
b) 2.44 s
c) 2.57 s
d) 25.117 m/s
Explanation:
t = Time taken
u = Initial velocity = 24 m/s
v = Final velocity
s = Displacement
a = Acceleration due to gravity = 9.81 m/s²
b)
Time taken by the ball to reach the highest point is 2.44 seconds
a)
The highest point reached by the ball above its release point is 29.36 m
c) Total height is 3+29.35 = 32.35 m
The ball reaches the ground 2.57 seconds after reaching the highest point
d)
The ball will hit the ground at 25.2117 m/s
(3.6 newton-second) / (600 newton) = 0.006 second
Answer:
Explanation:
the one thrown below the horizontal is going straight down, while the one above the horizontal will experience a projectile motion which will makes it move farther away from the building where it was projected.