Agustin visits Panama City, Florida, during the month of May. He feels a shore breeze blowing from theocean onto the beach. What
1 answer:
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Answer:
Decreases, Increases
Explanation:
Resistance is parallel can be calculated using
1/Req = 1/R1 + 1/R2 + 1/R3 +....
Then, as more resistor is added in parallel the equivalent resistance is reduced.
Let use a simple sample
Let all the resistor have equal resistances
Let say R = R1 = R2 = R3 =...Rn
Then, 1/Req = 1/R1 + 1/R2 + 1/R3 +....
1/Req = 1/R + 1/R + 1/R +.... 1/Rn
Req = R/n
Check attachment on how I got that.
This implies that, the equivalent resistance will always be less than the original resistance, since n>1
So, as n increases (I.e. as the number of resistance increases), the equivalent resistance reduces.
B. Now, to know if the current reduces or increases
Using Ohms law
V = iR
Then, I = V/R
So, let assume the voltage is constant, then, the current is inversely proportional to the resistance, so as we know that the resistance is reducing, then the current will be increasing.
So current increase as we add more resistor in parallel to a circuit
Answer:
Fn: magnitude of the net force.
Fn=30.11N , oriented 75.3 ° clockwise from the -x axis
Explanation:
Components on the x-y axes of the 17 N force(F₁)
F₁x=17*cos48°= 11.38N
F₁y=17*sin48° = 12.63 N
Components on the x-y axes of the the second force(F₂)
F₂x= −19.0 N
F₂y= 16.5 N
Components on the x-y axes of the net force (Fn)
Fnx= F₁x +F₂x= 11.38N−19.0 N= -7.62 N
Fny= F₁y +F₂y= 12.63 N +16.5 N = 29.13 N
Magnitude of the net force.
Direction of the net force (β)
β=75.3°
Magnitude and direction of the net force
Fn= 30.11N , oriented 75.3 ° clockwise from the -x axis
In the attached graph we can observe the magnitude and direction of the net force
Answer:
(a). Their speed during that run is 10 m/s.
(b). Their velocity is 6.86 m/s
(c). The final position is at 8.91 m.
Explanation:
Given that,
A football player starts at the 40-yard line, and runs to the 25-yard line in 2 seconds.
Suppose, the distance between 40 yard line and 25 yard line is 20 yard.
(a). We need to calculate their speed during that run
Using formula of speed
Where. d = distance
t = time
Put the value into the formula
during that run
(b). We need to calculate their velocity
Using formula of speed
Put the value into the formula
Negative sign shows the direction of motion.
(c). If they kept running at that velocity for another 1.3 seconds,
We need to calculate the final position
Using formula of position
Put the value into the formula
Hence, (a). Their speed during that run is 10 m/s.
(b). Their velocity is 6.86 m/s
(c). The final position is at 8.91 m.