Answer:
Mass of the cart = 146 kg
Explanation:
A cart is pulled by a force of 250 N at an angle of 35° above the horizontal.
The cart accelerates at 1.4 m/s² horizontally.
Horizontal force = Fcosθ = 250 cos35° = 204.79N
We have F = ma
Substituting
204.79 = m x 1.4
m = 146.28 kg = 146 kg
Mass of the cart = 146 kg
In solids: All metals are good conductors of electricity as they contain free moving electrons. Non-metals doesn't conduct , but we consider Graphite the only non-metal that can conduct electricity for the presence of free moving electrons.
In Liquids ; Ionic compunds contains free moving ions , so they conduct electricity as well .
Answer:
a) 
b) 
Explanation:
Part a
For this case we can begin finding the period like this:

Then we know that the centripetal acceleration is given by:

And the velocity is given by:

If we replace this into the acceleration we got:

And we can replace the values and we got:

Part b
For this case we want to find a value of k such that:

Where a = 9.74, so then we can solve for k like this:

<u>Solution and Explanation:</u>
The following calculation is made in order to find out the area and the final velocity vector.
Using the given information and the data in the question,
m1u1 + m2u2 = (m1 + m2) multiply with v
40000 multiply with ( -20i ) + 60000 multiply with ( 10j ) = 100000 multiply with v
Therefore, v = -8i + 6j
That is |v| = 10 knots towards the 36.86 degree north of the west
Answer:
1. 57.99V
2. 37.5Hz
3. 0.7072A
4. 82 ohms
5. 5.18x10^-5F
Explanation:
In answer to this question, we have the Standard equation of AC emf to be
V = V0 x sin ωt
We have
V0 = 82V,
ω = 75π
1.
RMS Voltage =
V0/√2 = 82 /√2
= 82/1.414
= 57.99V
2.
ω = 2π* f
75π = 2πf
Frequency,f = 75π/2π
= 235.5/6.28
= 37.5 Hz
3.
RMS current
= Imax/√2
= 1.00/1.414
= 0.7072A
4.
Reactance
= Vrms/ Irms
= 57.99/0.7072
= 81.999
= 82.0 Ω
5.
Reactance = 1/ ω x C
Reactance = 82
ω = 75π
We put these values into the equation above and make c the subject of the formula
C = 1/82.0 x 75π
C = 1/ 82.0 x 75 x 3.14
C = 1/19311
Capacitance = 5.18x10^-5F