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gavmur [86]
3 years ago
10

What kind of bond does these have?

Chemistry
1 answer:
RUDIKE [14]3 years ago
7 0
<span>1. Tap water has a small concentration of H+ & OH- ions as well as water molecules, hence there would be permanent dipole-permanent dipole (p.d.-p.d.) forces of attraction between the water molecules (aka H-bonds) as well as ionic bonds between the H+ & OH- ions.

2. Distilled water does not have H+ & OH- ions, hence only H-bonds exist between the water molecules.

3. There are covalent bonds between the individual sugar molecules.
 
4. There are ionic bonds between the Na+ & Cl- ions in NaCl.
 
5. There are p.d.-p.d. forces of attraction between the Na+ ions and the O2- partial ions of the water molecules as well as between the Cl- ions and the H+ partial ions of the water molecules. There are also H-bonds between the individual water molecules and ionic bonds between the Na+ & Cl- ions (although these are in much lower abundance than in unsolvated solid NaCl).

6. There are i.d.-i.d. as well as p.d.-p.d. forces of attraction between the sugar molecules and the water molecules. There are also H-bonds between the individual water molecules and covalent bonds within the sugar molecules.</span>
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At a certain temperature the rate of this reaction is first order in HI with a rate constant of :0.0632s2HIg=H2g+I2g Suppose a v
olya-2409 [2.1K]

Answer:

\boxed{\text{28.0 s}}

Explanation:

Whenever a question asks you, "How long does it take to reach a certain concentration?" or something like that, you must use the appropriate integrated rate law expression.

The integrated rate law for a first-order reaction is  

\ln \left (\dfrac{[A]_{0}}{[A]} \right ) = kt

Data:

[A]₀ = 1.28 mol·L⁻¹

[A] = 0.17 [A]₀

  k = 0.0632 s⁻¹

Calculation:

\begin{array}{rcl}\ln \left (\dfrac{[A]_{0}}{0.170[A]_{0}} \right ) & = & 0.0632t\\\\\ln \left (5.882) & = & 0.0632t\\1.772 & = & 0.0632t\\\\t & = & \dfrac{1.772}{0.0632}\\\\t & = & \textbf{{28.0 s}}\\\end{array}\\\text{It will take } \boxed{\textbf{28.0 s}} \text{ for [HI] to decrease to 17.0 \% of its original value.}

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3 years ago
Which law is associated with inertia
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Newton's first law is the answer.
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4 years ago
If the atomic radius of a calcium crystal is 180 pm, what is the length of the edge of the unit cell? (the calcium crystal forms
My name is Ann [436]
<span>Calcium crystal has a face center cubic (FCC) structure. For FCC structure,
relation between edge length (a) and radius (r) is
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<span>Given: r = 180 pm
Therefore, a = 2</span>√2 180
<span>                     = 2 x 1.141 x 180
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</span><span>The length of the edge of the Ca unit cell is 410.76 pm.</span><span>

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