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Snezhnost [94]
3 years ago
8

What mass of oxygen would be required for the complete combustion of 10 Grams of glucose?

Chemistry
1 answer:
enot [183]3 years ago
3 0

Answer:

For the complete combustion of 10 g of glucose 11.52 g of oxygen is required.

Explanation:

Given data:

Mass of glucose = 10 g

Mass of oxygen required for complete combustion = ?

Solution:

Chemical equation:

C₆H₁₂O₆ + 6O₂    →  6CO₂ + 6H₂O

Now we will convert the given mass of glucose into number of moles.

Number of moles = mass/ molar mass

Number of moles = 10 g/ 180.156 g/mol

Number of moles = 0.06 mol

Now we will compare the moles of glucose with oxygen.

         C₆H₁₂O₆            :              O₂

            1                     :               6

          0.06                :            6×0.06 = 0.36 mol

Mass of oxygen required:

Mass = number of moles × molar mass

Number of moles  = 0.36 mol × 32 g/mol

Number of moles = 11.52 g

For the complete combustion of 10 g of glucose 11.52 g of oxygen is required.

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6 0
3 years ago
Identify limiting and excess reagents when 25g of nitrogen reacts with 25g of hydrogen. How many grams of ammonia gas are formed
Makovka662 [10]

Answer:

Nitrogen is limiting reactant while hydrogen is in excess.

Explanation:

Given data:

Mass of N₂ = 25 g

Mass of H₂ = 25 g

Mass of ammonia formed = ?

Solution:

Chemical equation:

N₂ + 3H₂    →     2NH₃

Number of moles of Nitrogen:

Number of moles = mass/ molar mass

Number of moles = 25 g/ 28 g/mol

Number of moles = 0.89 mol

Number of moles of hydrogen:

Number of moles = mass/ molar mass

Number of moles = 25 g/ 2 g/mol

Number of moles = 12.5 mol        

Now we will compare the moles of both reactant with ammonia.

                   H₂            ;             NH₃

                    3             :              2

                    12.5        :            2/3×12.5 = 8.3

                 

                   N₂            ;             NH₃

                    1              :              2

                    0.89        :            2×0.89 = 1.78

The number of moles of ammonia produced by nitrogen are less thus nitrogen is limiting reactant while hydrogen is in excess.

7 0
3 years ago
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