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3 years ago

How many conversion factors can be created from one equivalence statement

Chemistry

1 answer:

lutik1710 [3]3 years ago

6 0

You can create two conversion factors from one equivalence statement.

For example, consider the equivalence statement

1 kg ≡ 1000 g

If you divide both sides by 1 kg, you get the conversion factor:

1 = 1000 g/1 kg.

If you divide both sides by 1000 g, you get the conversion factor:

1 kg/1000 g = 1.

Both of these are conversion factors because they both equal one, and multiplying a measurement by one does not change its value.

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3 years ago

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What is the boiling point of a 1.5 m aqueous solution of fructose? the boiling point elevation constant of water is 0.515Â°c/m.

GREYUIT [131]

Answer is: he boiling point of a 1.5 m aqueous solution of fructose is 100.7725°C.
The boiling point elevation is directly proportional to the molality of the solution according to the equation: ΔTb = Kb · b.
ΔTb - the boiling point elevation.
Kb - the ebullioscopic constant. of water.
b - molality of the solution.
Kb = 0.515°C/m.
b = 1.5 m.
ΔTb = 0.515°C/m · 1.5 m.
ΔTb = 0.7725°C.
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3 years ago

A student used 1.168g of an unknown weak acid and titrated it against 28.75 mL of 0.105M NaOH to reach the equivalence point. Wh

Vaselesa [24]

Answer:

The molar mass of the unknown acid is 386.8 g/mol

Explanation:

Step 1: Data given

Mass of the weak acid = 1.168 grams

volume of NaOH = 28.75 mL = 0.02875 L

Molarity of NaOH = 0.105 M

Since we only know 1 equivalence point, we suppose the acid is monoprotic

Step 2: Calculate moles NaOH

Moles NaOH = molarity NaOH * volume NaOH

Moles NaOH = 0.105 M * 0.02875 L

Moles NaOH = 0.00302 moles

We need 0.00302 moles of weak acid to neutralize the NaOH

Step 3: Calculate molar mass of weak acid

Molar mass = mass / moles

Molar mass = 1.168 grams / 0.00302 moles

Molar mass = 386.8 g/mol

The molar mass of the unknown acid is 386.8 g/mol

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3 years ago

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kati45 [8]

Answer: at higher temperatures.
Justification:

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2) The solution of a gas into a liquid is inversely related to the temperature: the lower the temperature the more gas gets dissolved.
So, in the manufacturing of soda, the CO₂ is added in cool water in a cool environment.

3) So, the higher the temperature after the soda is delivered, the more gas will be liberated when you open the can.

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4 years ago

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Tom [10]

Answer:

Keep temperature constant and increase the pressure of the reaction. The rate of reaction increases.

Explanation:

First of all, the question is asking us to design an experiment to investigate the effect of pressure on the rate of reaction hence the pressure can not be held constant since it is the variable under investigation. This eliminates the first option.

Secondly, increasing the pressure of the reaction means that particles of the gas collide more frequently leading to a greater number of effective collisions and a consequent increase in the rate of reaction according to the collision theory.

Hence the answer above.

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3 years ago