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Karolina [17]
3 years ago
6

Which of the following sets of units is appropriate for a second order rate constant?

Chemistry
1 answer:
den301095 [7]3 years ago
4 0

Answer:

C. Lmol^{-1}s^{-1}

Explanation:

According to the law of mass action:-

The rate of the reaction is directly proportional to the active concentration of the reactant which each are raised to the experimentally determined coefficients which are known as orders. The rate is determined by the slowest step in the reaction mechanics.

Order of in the mass action law is the coefficient which is raised to the active concentration of the reactants. It is experimentally determined and can be zero, positive negative or fractional.

The order of the whole reaction is the sum of the order of each reactant which is raised to its power in the rate law.

Given that:- order = 2

So,

r=K[A]^2

Units of rate of reaction = M/s

Units of [A] = M

So,

M/s=K\times (M)^2

Units of K = {Ms}^{-1}

Also, M = mol/L

So, units of second rate constant = Lmol^{-1}s^{-1}

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<u>Answer:</u>

It is the expression of Charles' Law.

<u>Explanation:</u>

The given expression V1T2 = V2T1 is the formula for the Charles' Law.

A special case of an ideal gas is named as the Charles' Law. This law applies to ideal gases only which are at constant pressure.

According to this law, the volume of a fixed mass of a gas is directly proportional to its temperature and is given by:

V1T2 = V2T1

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Answer:

C₆H₈O₆

Explanation:

First off, the<u> percent of oxygen by mass</u> of vitamin C is:

  • 100 - (40.9+4.58) = 54.52 %

<em>Assume we have one mol of vitamin C</em>. Then we would have <em>180 grams</em>, of which:

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Now we <u>convert each of those masses to moles</u>, using the <em>elements' respective atomic mass</em>:

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  • O ⇒ 98.136 g ÷ 16 g/mol = 6.134 mol O ≅ 6 mol O

So the molecular formula for vitamin C is C₆H₈O₆

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3 years ago
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Answer:

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Explanation:

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