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belka [17]
3 years ago
9

Which electron configuration represents an excited state for an atom for calcium

Chemistry
2 answers:
aev [14]3 years ago
6 0

The electron configuration represents an excited state for an atom for calcium is \boxed{{\text{2 - 8 - 7 - 3}}}.

Further explanation:

The electronic configuration is the distribution of electrons of an atom in the atomic orbitals. There are two states for an electron: ground as well as the excited state. The configuration of the atom in the lowest possible energy levels is called the ground-state electronic configuration.

When an electron jumps from the stable ground state to some higher level, that state is called the excited state and the electronic configuration corresponding to this state is known as the excited-state electronic configuration.

The filling of electrons in different energy levels or orbitals is done in accordance with the following three rules.

1.Aufbau principle.

2. Hund’s rule.

3. Pauli’s exclusion principle.

Calcium atom has an atomic number 20. Its stable electronic configuration will be 2, 8, 8, 2. The calcium atom has 20 electrons that are distributed into four shells. If the calcium is excited, the electron could gain energy and occupy the next available orbital. Due to this, one of the 8 electrons in the third shell gains energy and move to the fourth shell. The number of electrons presents in the third shell decrease by 1, while the number of electrons in the fourth shell increase by 1.

Electronic configuration of Calcium: 1{s^2}2{s^2}2{p^6}3{s^2}3{p^6}4{s^2}.

Electronic configuration of calcium for an excited state: 1{s^2}2{s^2}2{p^6}3{s^2}3{p^5}4{s^2}4{p^1}.

In the first shell, there is two s electron, in second shell there are two s and 6p electrons, in third shell, there are 2s and 5p electron and in fourth shell there are 2s and 1p electrons in the excited state of calcium.

Hence for an excited state the electronic configuration of calcium will become 2,8,7,3.

Learn more:

1. What happens to the reducing agent during redox reaction?:brainly.com/question/2890416

2. Identification of element which has electron configuration  :brainly.com/question/9616334

Answer details:

Grade: High School

Subject: Chemistry

Chapter: Electronic configuration of the elements

Keywords: monoatomic ion, neon, electronic configuration, Aufbau principle, Hund’s rule, Pauli’s exclusion principle, calcium, 20, 2,8,8,2 and 2,8,7,3.

vaieri [72.5K]3 years ago
5 0

The electron configuration that represent an excited state for an atom of calcium is 2, 8, 7, 3.

Calcium atom has an atomic number of 20 and its electronic configuration is 2, 8, 8, 2. An atom is said to be in an excited state if it gains energy and move to an higher energy level. For the calcium atom given above, there are 20 electrons which are distributed into four shells. But in the excited state [option 3], one of the 8 electrons in the third shell gains energy and move to the fourth shell. Thus, the number of electrons in the third shell reduced by 1, while the number of electrons in the fourth shell increase by 1.

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Explanation:

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givi [52]

Answer:

According to their expected pKa values, the order of those acids should be:

1- Cl2CHCOOH is the strongest acid and the lowest pKa.

2- ClCH2COOH is a strong acid, but no more than the first. Medium pKa value.

3- ClCH2CH2COOH is a strong acid, but no more than the two previous acids. High pKa value.

4- CH3CH2COOH  is the weakest acid, so the highest pKa value.

Explanation:

The pKa values are the negative logarithm of dissociation constant. It represents the relative strengths of the acids. Stronger acids show smaller pKa values and weak acids present larger pKa value. The stronger the acid, the weaker it's the conjugate base. The larger the pKa of the conjugate base, the stronger the acid. The strength of an acid is inversely related to the strength of its conjugate.

Conjugate bases are the substance that has one less proton than the parent acid. The conjugate base of the acid presented in the problem are:

ClCH2COOH -> ClCH2COO-  + H+

ClCH2CH2COOH -> ClCH2CH2COO- + H+

CH3CH2COOH -> CH3CH2COO- + H+

Cl2CHCOOH -> Cl2CHCOO - + H+

Cl2CHCOOH. The negative charge presented on its conjugate base is by resonance and inductive effect. This is the strongest acid.

ClCH2COOH. A negative charge is stabilized by resonance and electron-withdrawing but only one atom is present. So this acid is less strong than the first one.

ClCH2CH2COOH. The negative charge is stabilized by resonance and electron-withdrawing atom but the effect is less compared to the two acids showed previously.

CH3CH2COOH. The negative charge is stabilized by resonance and destabilized due to CH3 group. This is the weakest acid among the problem.

Stronger acids have smaller pKa values and weak acids have larger pKa values. Due to the information present in this problem, Cl2CHCOOH is the strongest acid and the lowest pKa. CH3CH2COOH is the weakest acid, so the highest pKa value.

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1- Cl2CHCOOH is the strongest acid and the lowest pKa.

2- ClCH2COOH is a strong acid, but no more than the first. Medium pKa value.

3- ClCH2CH2COOH is a strong acid, but no more than the two previous acids. High pKa value.

4- CH3CH2COOH  is the weakest acid, so the highest pKa value.

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