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4 years ago

3. What average net force is required to stop a 7 kg shopping cart in 2 s if it's initially

Physics

1 answer:

Mashcka [7]4 years ago

5 0

Answer:

The force required to stop the shopping cart is, F = 12.25 N

Explanation:

Given data,

The mass of the shopping cart, m = 7 kg

The initial velocity of the shopping cart, u = 3.5 m/s

The final velocity of the shopping cart, v = 0 m/s

The time period of acceleration, t = 2 s

The change in momentum of the cart,

p = m(u - v)

= 7 (3.5 - 0)

= 24.5 kg m/s

The force is defined as the rate of change of momentum. To stop the shopping cart, the force required is given by the formula

F = p / t

= 24.5 / 2

= 12.25 N

Hence, the force required to stop the shopping cart is, F = 12.25 N

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Dafna1 [17]

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4 years ago

A capacitor with air between its plates ischarged to 60 V and then disconnected fromthe battery. When a piece of glass is placed

-BARSIC- [3]

Answer:

k = 1.30

Explanation:

For this exercise let's write the capacitance in air and with dielectric

air C₀ = Q / DV

dielectric C = k Q / DV

They tell us that the capacitor is charged and then the battery is disconnected, therefore the charge stored on the plate remains constant.

therefore the capacitance a changes to the value

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3 years ago

What happens to the gravitational force between two masses when the distance between the masses is doubled?

vovangra [49]

Answer:

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Explanation:

The gravitational force between two masses is given by

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where

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In this problem, the distance between the masses is doubled, so

r' = 2r

Substituting into the equation, we see that the new force is

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3 years ago

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