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EastWind [94]
4 years ago
10

3. What average net force is required to stop a 7 kg shopping cart in 2 s if it's initially

Physics
1 answer:
Mashcka [7]4 years ago
5 0

Answer:

The force required to stop the shopping cart is, F = 12.25 N

Explanation:

Given data,

The mass of the shopping cart, m = 7 kg

The initial velocity of the shopping cart, u = 3.5 m/s

The final velocity of the shopping cart, v = 0 m/s

The time period of acceleration, t = 2 s

The change in momentum of the cart,

                                       p = m(u - v)

                                          = 7 (3.5 - 0)

                                          = 24.5 kg m/s

The force is defined as the rate of change of momentum. To stop the shopping cart, the force required is given by the formula

                                            F = p / t

                                                = 24.5 / 2

                                                = 12.25 N

Hence, the force required to stop the shopping cart is, F = 12.25 N

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bekas [8.4K]

The correct answer is the following.

The forces that act on the piano are: 2) gravitational force acting on the piano (piano's weight). 5) force of the floor on the piano (normal force). 7) force of Chadwick on the piano.

As we see in the picture that I have attached is Chadwick pushing the piano in a horizontal plane. So Chadwick is applying a force that produces an acceleration. It is his force on the piano plus the acceleration of the weight of the piano, it's a gravitational force. This is pure physics applied to an object.

5 0
3 years ago
A uniform thin rod of length 0.11 m and mass 4.6 kg can rotate in a horizontal plane about a vertical axis through its center. T
ale4655 [162]

Answer:

Explanation:

This problem is based on conservation of rotational momentum.

Moment of inertia of rod about its center

= 1/12 m l² , m is mass of the rod and l is its length .

= 1 / 12 x 4.6 x .11²

I = .004638 kg m²

The angular momentum of the bullet about the center of rod = mvr

where m is mass , v is perpendicular component of velocity of bullet and r is distance of point of impact of bullet fro center .

5 x 10⁻³ x v sin60 x .11 x .5  where v is velocity of bullet

According to law of conservation of angular momentum

5 x 10⁻³ x v sin60 x .11 x .5 = ( I + mr²)ω , where ω is angular velocity of bullet rod system and  ( I + mr²) is moment of inertia of bullet rod system .

.238 x 10⁻³ v = ( .004638 + 5 x 10⁻³ x .11² x .5² ) x 12

.238 x 10⁻³ v = ( .004638 + .000015125 ) x 12

.238 x 10⁻³ v = 55.8375 x 10⁻³

.238 v = 55.8375

v = 234.6 m /s

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Your cars streering wheel can be used to change your cars velocity. True or false? I kind confuse
podryga [215]
False , the gas petal makes the speed go up
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Ne4ueva [31]

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3 years ago
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What is the magnetic force value due to 3.5nanocoloumb charge moves to the
sertanlavr [38]

The force on the charge is 1.1×10⁻⁸ N.

<h3>What is force?</h3>

Force can be defined as the product of the mass of a body and its acceleration

To calculate the force on the charge, we use the formula below.

Formula:

  • F = qvBsin∅............. Equation 1

Where:

  • q = charge
  • v = velocity
  • B = magnetic field
  • ∅ = Angle.

From the question,

Given:

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  • v = 250 m/s
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  • ∅ = 30°

Substitute the given values into equation 1

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Hence, the force on the charge is 1.1×10⁻⁸ N.

Learn more about force here: brainly.com/question/12970081




6 0
3 years ago
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