Answer:
The type of decay illustrated by the equation is a Beta decay.
Option B is correct.
Explanation:
Complete Question
What type of decay is illustrated by the equation below?
²¹⁴₈₃Bi → ²¹⁴₈₄Po + ⁰₋₁e
- alpha decay
- beta decay
- positron emission
- electron capture
Solution
The type of radioactive decay is usually discernable from studying the products and reactants (the parent nucleus/atom, the daughter nucleus and the emitted or absorbed particles) of the radioactive decay.
The changes in atomic and mass numbers is accounted for in the particular particle that that is emitted and subsequently termed the type of radioactive decay that is going on.
For example, this equation represented shows that the Bi atom splits into a Po and a Beta particle. Hence, it is easy and straight forward to see that this radioactive decay is to relaese a Beta particle and the decay is a Beta decay.
(Note that, just as presented in the equation, a Beta particle has a mass number of 0 and an atomic number -1, kind of similar to an electron).
- An alpha decay releases an alpha particle.
- A beta decay releases a Beta particle.
- A positron emission releases a positron.
- An electron capture involves an electron attacking the parent atom/nucleus or the reactant.
Hope this Helps!!!
Except for mass, length, time, and electric charge, EVERY quantity is
a combination of units ... of THOSE units in fact. Hadn't you noticed ?
Answer:
Fluid Friction
Explanation:
The kind of friction that occurs when a fish swims through water is fluid friction. The name alone is a giveaway since water is a fluid. By definition, fluid friction is the resistance to an object's movement through a fluid, where a resistance to a movement through fluid is also termed as viscous resistance.
<h2>
Option C is the correct answer.</h2>
Explanation:
Consider the vertical motion of rock,
We have equation of motion s = ut + 0.5 at²
Initial velocity, u = 0 m/s
Acceleration, a = 9.81 m/s²
Displacement, s = 20 m
Substituting
s = ut + 0.5 at²
20 = 0 x t + 0.5 x 9.81 x t²
t = 2 s
After 2 seconds it reaches ground,
Now consider the horizontal motion of rock,
We have equation of motion s = ut + 0.5 at²
Initial velocity, u = 10 m/s
Acceleration, a = 0 m/s²
Time, t = 2 s
Substituting
s = ut + 0.5 at²
s = 10 x 2 + 0.5 x 0 x 2²
s = 20 m
Distance traveled is 20 m
Horizontal distance traveled = 20 m
Option C is the correct answer.
B will have the greater force
Fc=MV2 /R=Fm
The A particle has less centipetal force and larger radius so larger curve
