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inna [77]
3 years ago
9

Write the energy conversion when climbing a ladder​

Physics
1 answer:
Volgvan3 years ago
7 0
A child climbing a ladder is transforming kinetic energy into potential energy.
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What is an equilibrant?
Stolb23 [73]
I’m pretty sure it is an object with a net force of zero. All forces are balanced and EQUAL
4 0
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There is no law of conservation​
ruslelena [56]

Answer:

yes

Explanation:

I think so because it not mention in the law

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3 years ago
An unstretched spring has a length of 0.30 m. When the spring is stretched to a total length of 0.60 m, it supports traveling wa
IceJOKER [234]

Explanation:

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3 years ago
An 85.0 kg fisherman jumps from a dock at a speed of 4.30 m/s onto their 135.0 kg boat. If the boat was at rest to begin but mov
jeka94

Answer:

Final speed of boat + man is 1.66 m/s

Explanation:

As we know that there is no friction on the system or there is no external force on this system

So here we can use momentum conservation here

mv = (m + M)v_f

so we have

m = 85 kg

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4 0
3 years ago
Proposed Exercise - Circular Movement
notka56 [123]

Answer:

ωB = 300 rad/s

ωC = 600 rad/s

Explanation:

The linear velocity of the belt is the same at pulley A as it is at pulley D.

vA = vD

ωA rA = ωD rD

ωD = (rA / rD) ωA

Pulley B has the same angular velocity as pulley D.

ωB = ωD

The linear velocity of the belt is the same at pulley B as it is at pulley C.

vB = vC

ωB rB = ωC rC

ωC = (rB / rC) ωB

Given:

ω₀A = 40 rad/s

αA = 20 rad/s²

t = 3 s

Find: ωA

ω = αt + ω₀

ωA = (20 rad/s²) (3 s) + 40 rad/s

ωA = 100 rad/s

ωD = (rA / rD) ωA = (75 mm / 25 mm) (100 rad/s) = 300 rad/s

ωB = ωD = 300 rad/s

ωC = (rB / rC) ωB = (100 mm / 50 mm) (300 rad/s) = 600 rad/s

5 0
3 years ago
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