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ololo11 [35]
3 years ago
14

El momento lineal de un coche que viaja hacia el norte a 20m/s es distinto al momento lineal del mismo auto viajando hacia el es

te con la misma rapidez.
Physics
1 answer:
Jobisdone [24]3 years ago
4 0

Explanation:

The momentum of any object is given by the product of mass and velocity with which it is moving i.e.

p = mv

Momentum is a vector quantity. It means we can resolve it into rectangular components.

If the car is moving with a speed of 20 m/s in North direction, its momentum is given by :

p_y=20m\ \hat{j}\ kg-m/s .....(1)

If the car is moving with a speed of 20 m/s in East direction, its momentum is given by :

p_x=20m\ \hat{x}\ kg-m/s ....(2)

It is clear from equation (1) and (2) that the magnitude of momentum is same but the direction of momentum is different in both cases.

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Two people stand facing each other at a roller skating rink then push off each other. a). What is the momentum of the system bef
Semenov [28]

Explanation:

hindi ko po alam yun e show pic mo

8 0
2 years ago
3. As the duration of a maximal effort increases from 10 seconds or less to between 10 and 180 seconds, what factor becomes limi
Molodets [167]

Answer:

Anaerobic energy

Explanation:

Anaerobic energy is produced at maximal effort within a very short period, anaerobic energy is energy produced when effort is expended at quick bursts and usually less than 10 seconds.

Therefore, if maximal effort time is increased beyond 10 seconds, the energy produced is not anaerobic and as such, anaerobic energy is limited.

7 0
3 years ago
3. Some guitarists like the feel of a set of strings that all have the same tension. For such a guitar, the G string (196 Hz) ha
Vlad [161]

Answer:

0.98 g/m

Explanation:

Note: Since Tension and frequency are constant,

Applying,

F₁²M₁ = F₂²M₂............... Equation 1

Where F₁ = Frequency of the G string, F₂ = Frequency of the A string, M₁ = mass density of the G string, M₂ = mass density of the A string.

make M₂ the subject of the equation

M₂ = F₁²M₁/F₂²............... Equation 2

From the question,

Given: F₁ = 196 Hz, M₁ = 0.31 g/m, F₂ = 110 Hz

Substitute these values into equation 2

M₂ = 196²(0.31)/110²

M₂ = 0.98 g/m

4 0
3 years ago
Calculate the gravitational potential energy of a body of mass 40 kg at a vertical height of 10 m. ( g = 9.8 m/s2)
olganol [36]
Ep= mgh
Ep = 40 x 9.8 x 10
Ep = 3920J
Ep = 3900J (2sf)
8 0
3 years ago
A train slows down as it rounds a sharp horizontal turn, going from 94.0 km/h to 46.0 km/h in the 17.0 s that it takes to round
Svetllana [295]

Answer:

1.41 m/s^2

Explanation:

First of all, let's convert the two speeds from km/h to m/s:

u = 94.0 km/h \cdot \frac{1000 m/km}{3600 s/h} = 26.1 m/s

v=46.0 km/h \cdot \frac{1000 m/km}{3600 s/h}=12.8 m/s

Now we find the centripetal acceleration which is given by

a_c=\frac{v^2}{r}

where

v = 12.8 m/s is the speed

r = 140 m is the radius of the curve

Substituting values, we find

a_c=\frac{(12.8 m/s)^2}{140 m}=1.17 m/s^2

we also have a tangential acceleration, which is given by

a_t = \frac{v-u}{t}

where

t = 17.0 s

Substituting values,

a_t=\frac{12.8 m/s-26.1 m/s}{17.0 s}=-0.78 m/s^2

The two components of the acceleration are perpendicular to each other, so we can find the resultant acceleration by using Pythagorean theorem:

a=\sqrt{a_c^2+a_t^2}=\sqrt{(1.17 m/s^2)+(-0.78 m/s^2)}=1.41 m/s^2

6 0
3 years ago
Read 2 more answers
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