As to the third law every object has an equal and opposite reaction. therefore the the stone is forwarded as a result of the force applied. as to the first law, an object in motion will move at uniform velocities because of the unbalanced force. As to 2nd law, the acceleration is directly proportioal to magnitude of the net force. therefore the more force you apply from the catapault, the further it will go.'
The answer is 1000/20. Or that’s what I’m guessing. Lol
Answer:
Explanation:
For lens A
object distance u = - 13.1 cm , focal length f = 6.19 cm
From lens formula
1/v - 1/u = 1/f
1 / v + 1/13.1 = 1/6.19
1/v = 1/6.19 - 1/13.1
= .16155 - .07633
= .08522
v = 11.7 3 cm
For lens B
object distance u = - ( 55.7 - 11.73) = - 43.97 cm , focal length f = 27.9 cm
From lens formula
1/v - 1/u = 1/f
1 / v + 1/43.97 = 1/27.9
1/v = 1/27.9 - 1/43.97
= .03584 - .022742
= .013098
v = 76.35 cm
Image will be formed 76.35 cm behind lens B .
magnification of lens system
= m₁ x m₂ , m₁ is magnification by lens A and m₂ is magnification by lens B
= (11.73 / 13.1) x (76.35 / 43.97)
= .8954 x 1.73
= 1.5547
size of image = total magnification x size of object
= 1.5547 x 6.47
= 10 cm approx. The first image will be real and inverted and second image will be erect with respect to object.