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ololo11 [35]
3 years ago
14

El momento lineal de un coche que viaja hacia el norte a 20m/s es distinto al momento lineal del mismo auto viajando hacia el es

te con la misma rapidez.
Physics
1 answer:
Jobisdone [24]3 years ago
4 0

Explanation:

The momentum of any object is given by the product of mass and velocity with which it is moving i.e.

p = mv

Momentum is a vector quantity. It means we can resolve it into rectangular components.

If the car is moving with a speed of 20 m/s in North direction, its momentum is given by :

p_y=20m\ \hat{j}\ kg-m/s .....(1)

If the car is moving with a speed of 20 m/s in East direction, its momentum is given by :

p_x=20m\ \hat{x}\ kg-m/s ....(2)

It is clear from equation (1) and (2) that the magnitude of momentum is same but the direction of momentum is different in both cases.

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Read 2 more answers
A 6.47-mm-high firefly sits on the axis of, and 13.1 cm in front of, the thin lens A, whose focal length is 6.19 cm. Behind lens
bagirrra123 [75]

Answer:

Explanation:

For lens A

object distance u = - 13.1 cm , focal length f = 6.19 cm

From lens formula

1/v - 1/u = 1/f

1 / v + 1/13.1 = 1/6.19

1/v = 1/6.19 - 1/13.1

= .16155 - .07633

= .08522

v = 11.7 3 cm

For  lens B

object distance u = - ( 55.7 - 11.73) = - 43.97 cm , focal length f = 27.9 cm

From lens formula

1/v - 1/u = 1/f

1 / v + 1/43.97 = 1/27.9

1/v = 1/27.9 - 1/43.97

= .03584 - .022742

= .013098

v = 76.35 cm

Image will be formed 76.35 cm behind lens B .

magnification of lens system

= m₁ x m₂ , m₁ is magnification by lens A and m₂ is magnification by lens B

= (11.73 / 13.1) x (76.35 / 43.97)

= .8954 x 1.73

= 1.5547

size of image = total magnification x size of object

= 1.5547 x 6.47

= 10 cm approx. The first image will be real and inverted and second image will be erect with respect to object.

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