Answer:
-250.3kJ
Explanation:
Based in the reactions and using -<em>Hess's law-</em>:
(1) P₄(s) + 6 Cl₂(g) → 4PCl₃(g) ΔH₁ = -4439kJ
(2) 4PCl₅(g) → P₄(s) + 10Cl₂ ΔH₂ = 3438kJ
The sum of (1) + (2) is:
4PCl₅(g) → 4PCl₃(g) + 4 Cl₂ ΔH = -4439kJ + 3438kJ = -1001kJ
Dividing this reaction in 4:
PCl₅(g) → PCl₃(g) + Cl₂ ΔH = -1001kJ / 4 = <em>-250.3kJ</em>
Answer:
I
Explanation:
Among the halogens given in this problem, iodine has the lowest attraction for electrons.
This property is known as electronegativity.
Electronegativity is expressed as the relative tendency with which the atoms of the element attracts valence electrons in a chemical bond.
- As you go down the periodic group the electronegativity decreases.
- The most electronegative element on the periodic table is fluorine.
- Down the group, iodine is the least electronegative
- This is due to the large size of its atom.
Answer:
AWWWWWWWWWWWWWWWW SOOO NICEEE
