Answer:
4.3 m/sec
Explanation:
Here height of cliff = y = 37.6 m
Gravitational acceleration = g = 9.8 m/sec2
vi = 0 m/s
Let's find the time which the diver will take if jumps from there!
Using formula
y = vit+1/2gt2
==> 37.6= 0 + 0.5 ×9.8×
==>
=
==> t = 2.8 sec
In this time the diver has to cover a horizontal distance of 12.12 m
If x = 12.12 m is the horizontal distance to be covered then using
x= Vx × t
==> Vx = x/t
==> Vx= 12.12/2.8 = 4.3 m/s
Car with a mass of 1210 kg moving at a velocity of 51 m/s.
2. What velocity must a 1340 kg car have in order to have the same momentum as a 2680 kg truck traveling at a velocity of 15 m/s to the west? 3.0 X 10^1 m/s to the west.
Hope i helped
Have a good day :)
Answer:
the answer is 2000Nm
Explanation:
wprk done = force × distance moved
w.d = 200N × 10m
w.d = 2000Nm
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Answer: It would be 12 m/s.
Explanation: It would be this because If you go from rest to sprint it would be 12 m/s. Also, I did this the other day.