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Mariulka [41]
3 years ago
7

The current in an electric hair dryer is 10

Physics
1 answer:
Vikki [24]3 years ago
8 0
First let's convert the time in seconds:
\Delta t= 5 min= 5 min \cdot (60 s/min)= 300 s

The current is defined as the quantity of charge flowing through a certain section of a circuit per unit of time:
I= \frac{Q}{\Delta t}
Using I=10 A, and \Delta t=300 s, we can find the amount of charge flown through the hair dryer in this time:
Q=I \Delta t=(10 A)(300 s)=3000 C

The charge of a single electron is q=1.6 \cdot 10^{-19} C, so the number of electrons flown through the hair dryer is the total charge divided by the charge of a single electron:
N= \frac{Q}{q}= \frac{3000 C}{1.6 \cdot 10^{-19} C} =1.88 \cdot 10^{22}
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ΔF=125.22 %

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All other quantity are constant so we can say that drag force and velocity can be given as

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Now by putting the values

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Percentage Change in the drag force

\Delta F=\dfrac{F_D_2-F_D_1}{F_D_1}\times 100

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3 years ago
A frictionless pendulum is made with a bob of mass 19.7 kg. The bob is held at height = 0.934 meter above the bottom of its traj
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Energy=PE+KE=mgh+ 0.5mv^{2} where KE is kinetic energy, PE is potential energy, m is the mass of an object, v is the speed, h is the height and g is acceleration due to gravity.

Substituting 19.7 Kg for mass, 0.934 for h, 2.93 for v and 9.81 for g then

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