Answer:
, pfx = pix + Jx.
Explanation:
The momentum principle tells us that impulse transfers momentum to an object.
If an object has 2 kgm/s of momentum, a 1 kgm/s impulse delivered to the object
increases its momentum to 3 kgm/s. That is, pfx = pix + Jx.
Just as we did with energy, we can represent this “momentum accounting” with a
momentum bar chart. For example, the bar chart of FIGURE 11.6 represents the ball
colliding with a wall in Figure 11.4. Momentum bar charts are a tool for visualizing
an interaction
The distance travelled by the body on last second of its upwards journey is 4.935m
What is projectile motion?
A projectile is an object or particle that is launched toward the surface of the Earth and moves along a curved path only under the influence of gravity.
To solve this question, consider the horizontal distance to be H and
distance traveled by the body in the last second be d


H=510.2m
Now time taken to reach a height of
510.2 m= ![\sqrt[n]{2H/g}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7B2H%2Fg%7D)
=10.2 seconds
Now,



d=4936m
So, the correct answer is '4.936m'.
To know more about projectile motion visit:
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Answer:
0.366×10^{-3} / s
Explanation:
θ = θmax e^{-bt/2m}
Given that
θ = 5.50°
θmax = 15.0°
So that we have
ln (θ / θmax) = -bt /2m
= - ln(5.50°/ 15.0°) / 1000s = b /2m
= b / 2m = 0.366×10^{-3} / s
Answer:
2406 miles
Explanation:
Let A be the starting position, B the junction position and C the final position after flying the 3.5 hrs. Also, let b be the distance from the starting point:

#Distance traveled in 1.5hrs is;

#Distance traveled in next two hrs:

#Now using the Cosine Rule:

Hence, the pilot is 2406 miles from her starting position.
The troposphere is the lowermost layer of the Earth's atmosphere. Most of the weather phenomena, systems, convection, turbulence and clouds occur in this layer, although some may extend into the lower portion of the stratosphere.