Question

The number of lattes sold daily for two coffee shops is shown in the table:

Answer 1

Answer:

0.5

Step-by-step explanation:

Sort the given data in ascending order:

47, 48, 50, 52, 53, 53, 55, 68

Possible outlier is number 68. Check whether this number is an outlier:

$Q_1=49\\ \\Q_2=52.5 \\ \\Q_3=54$

The interquartile range is

$Q_3-Q_1=54-49=5$

Multiply it by 1.5:

$1.5\cdot 5=7.5$

and add to third quartile:

$7.5+54=61.5$

Since $68>61.5,$ number 68 is an outlier.

The median of the sample with outlier is $Q_2=\dfrac{52+53}{2}=52.5$

The median of the sample without outlier is 52

The difference between the median of the data, including the possible outlier and excluding the possible outlier is 52.5-52=0.5