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Romashka [77]
3 years ago
10

A 2.0-kg ball has a momentum of 25kg.m/s what is the ball's speed?

Physics
2 answers:
Reil [10]3 years ago
5 0

We know, momentum = mass * speed

25kgm/s = 2 kg * s

s = 25/2 = 12.5 m/s

Mazyrski [523]3 years ago
5 0

The ball's speed is about 13 m/s

\texttt{ }

<h3>Further explanation</h3>

Newton's second law of motion states that the resultant force applied to an object is directly proportional to the mass and acceleration of the object.

\large {\boxed {F = ma }

<em>F = Force ( Newton )</em>

<em>m = Object's Mass ( kg )</em>

<em>a = Acceleration ( m )</em>

\texttt{ }

\large {\boxed {F = \frac{\Delta p}{t} }

<em>F = Force ( Newton )</em>

<em>p = Momentum of Object ( kg m/s )</em>

<em>t = Time Taken ( s )</em>

Let us now tackle the problem !

\texttt{ }

<u>Given:</u>

mass of ball = m = 2.0 kg

momentum of ball = p = 25 kgm/s

<u>Asked:</u>

speed of the ball = ?

<u>Solution:</u>

<em>We could use formula for </em><em>momentum</em><em> to solve this problem:</em>

p = m v

v = p \div m

v = 25 \div 2.0

v = 12.5 \texttt{ m/s}

v \approx 13 \texttt{ m/s}

\texttt{ }

<h3>Conclusion :</h3>

The ball's speed is about 13 m/s

\texttt{ }

<h3>Learn more</h3>
  • Impacts of Gravity : brainly.com/question/5330244
  • Effect of Earth’s Gravity on Objects : brainly.com/question/8844454
  • The Acceleration Due To Gravity : brainly.com/question/4189441
  • Newton's Law of Motion: brainly.com/question/10431582
  • Example of Newton's Law: brainly.com/question/498822

\texttt{ }

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Dynamics

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A man is standing on the edge of a 20.0 m high cliff. He throws a rock horizontally with an initial velocity of 10.0 m/s.
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Answer:

<em>a. The rock takes 2.02 seconds to hit the ground</em>

<em>b. The rock lands at 20,2 m from the base of the cliff</em>

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\displaystyle t=\sqrt{\frac{2h}{g}}

The range is defined as the maximum horizontal distance traveled by the object and it can be calculated as follows:

\displaystyle d=v.t

The man is standing on the edge of the h=20 m cliff and throws a rock with a horizontal speed of v=10 m/s.

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The time taken by the rock to reach the ground is:

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b.

The range is calculated now:

\displaystyle d=10\cdot 2.02

d = 20.2 m

The rock lands at 20,2 m from the base of the cliff

5 0
3 years ago
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