Answer:I would prefer ginger with lemon and honey tea...Stay hydrated,Rest,
Explanation:
Answer:
The answer is -0.5m/s2
Explanation:
I did the test and got it right.
Hey there,
Your question states: <span>Debbie places two shopping carts in a cart corral. She pushes the first cart, which then pushes a second cart. What force is being exerted?
based by looking at this statement above about Debbie, I understand that she (pushed) Cart (A) first. And then, she exerted (Cart B) next. From the option's that are listed above, I only see two. But from my own words, not from the only (two) options above, I see that (Debbie first exerts the second cart on to the first cart). This reason would be because the first cart is already in the corral. So then she would put the second one in there, this would mean that the second one would push the other one in there. Which means that the velocity would also be in half.
I hope you grabbed my answer in there.
~Jurgen</span>
Answer:
As each mower presumably needs the same torque to start, and torque is a product of force and moment arm, the longer moment arm of 10.42 cm on Uwi's mower means lower force is required when compared to Urippe's shorter moment arm of 1.35 cm
350 rev/min = 350(2π) / 60 = 36.652 rad/s
36.652 rad/s / 0.294 s = 124.66... <u>125 rad/s²</u>
a = αR = 125(0.1042) = 12.990... <u>13 m/s²</u>
a = αR = 125(0.0135) = 1.68299... <u>1.7 m/s²</u>
I am GUESSING that we are supposed to model these mowers as a uniform disk
τ = Iα
FR = (½mr²)α
F = mr²α/2R
Urippe's pull = (3.56)(0.2041²)(124.66) / (2(0.0135)) = 702.008... <u>702 N</u>
Usi's pull = (3.56)(0.2041²)(124.66) / (2(0.1042)) = 90.9511...<u>91.0 N</u>
L = Iω = (½(3.56)(0.2041²))36.652 = 2.71771...<u>2.72 kg•m²/s down</u>
using the right hand rule
