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tia_tia [17]
3 years ago
15

two boys started runing stright to ward each other from two pionts 100m aparts.one run at speed of 4m/s and other at 6m/s.how fa

r are they from the slower one's starting point when they meet​
Physics
1 answer:
kodGreya [7K]3 years ago
6 0

Answer:

One boys rate is "r" and the other's is (r+10)

the distance they cover is 240 miles in 3 hours

3r + 3*(r+10) = 240

6r + 30 = 240

6r = 210

r = 35 mph and the faster car is

r + 10 = 45 mph

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What happens when you change the number of electrons in an atom
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<h2>Answer: It becomes an Ion </h2>

When an atom has gained or lost electrons (negative charge), it becomes an ion.

In this sense:

<h2>Ions are atoms that have <u>gained or lost</u> electrons in their electronic cortex. </h2><h2> </h2>

If a neutral atom <u>loses electrons</u>, it remains with an excess of positive charge and transforms into a positive ion or <u>cation</u>, whereas if a neutral atom <u>gains electrons</u>, it acquires an excess of negative charge and transforms into a negative ion or <u>anion</u>.

It is then how ions form bonds with other atoms differently depending on the number of electrons they have.

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Random errors can be reduced by taking repeated measurements.Error and uncertainty are interchangeable words that describe the s
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repeated mesurement can reduce the error

it is true

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1 year ago
Which activity is best described as a scientific endeavor?
Kipish [7]

Answer:

B

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https://gscourses.thinkific.com

8 0
3 years ago
6. A 2-kg ball B is traveling around in a circle of radius r1 = 1 m with a speed (vB)1 = 2 m/s. If the attached cord is pulled d
kipiarov [429]

Answer:

Explanation:

Given that,

Mass of ball m = 2kg

Ball traveling a radius of r1= 1m.

Speed of ball is Vb = 2m/s

Attached cord pulled down at a speed of Vr = 0.5m/s

Final speed V = 4m/s

Let find the transverse component of the final speed using

V² = Vr²+ Vθ²

4² = 0.5² + Vθ²

Vθ² = 4²—0.5²

Vθ² = 15.75

Vθ =√15.75

Vθ = 3.97 m/s.

Using the conservation of angular momentum,

(HA)1 = (HA)2

Mb • Vb • r1 = Mb • Vθ • r2

Mb cancels out

Vb • r1 = Vθ • r2

2 × 1 = 3.97 × r2

r2 = 2/3.97

r2 = 0.504m

The distance r2 to the hole for the ball to reach a maximum speed of 4m/s is 0.504m

The required time,

Using equation of motion

V = ∆r/t

Then,

t = ∆r/Vr

t = (r1—r2) / Vr

t = (1—0.504) / 0.5

t = 0.496/0.5

t = 0.992 second

7 0
3 years ago
Homer Agin leads the Varsity team in home runs. In a recent game, Homer hit a 34.5 m/s sinking curve ball head on, sending it of
Aneli [31]

Answer:

–77867 m/s/s.

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 34.5 m/s

Final velocity (v) = –23.9 m/s

Time (t) = 0.00075 s

Acceleration (a) =?

Acceleration is simply defined as the rate of change of velocity with time. Mathematically, it is expressed as:

Acceleration = (final velocity – Initial velocity) /time

a = (v – u) / t

With the above formula, we can obtain acceleration of the ball as follow:

Initial velocity (u) = 34.5 m/s

Final velocity (v) = –23.9 m/s

Time (t) = 0.00075 s

Acceleration (a) =?

a = (v – u) / t

a = (–23.9 – 34.5) / 0.00075

a = –58.4 / 0.00075

a = –77867 m/s/s

Thus, the acceleration of the ball is –77867 m/s/s.

3 0
3 years ago
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