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3 years ago

You serve a volleyball with a mass of 1.4 kg. The ball leaves with a speed of 13 m/s. Calculate KE

Physics

1 answer:

NemiM [27]3 years ago

7 0

Answer:

118.3 J

Explanation:

Givens:

m = 1.4 kg

V = 13 m/s

Formula for kinetic energy:

KE = (1/2)*(m)*(v)^2

KE = .5*(1.4 kg)*(13 m/s)^2

KE 118.3 J

J = Joules

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What is the smallest radius of an unbanked (flat) track around which a bicyclist can travel if her speed is 29.0 km/h and the co

bazaltina [42]

Answer:

Explanation:

Let the radius of track required be r.

Centripetal force will be provided by frictional force which will be equal to

m v²/ r

Frictional force = mg x μ

m v² /r = mg μ

r = v² / μ g =

v = 29 km /h = 8.05 m /s

r =( 8.05 x 8.05 ) /( .32 x 9.8 ) = 20.66 m

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2 years ago

Two boxes (24 kg and 62 kg) are being pushed across a horizontal frictionless surface, as the drawing shows. The 36-N pushing fo

defon

Answer:

$F = 26.04 N$

Explanation:

As we know that system of two boxes are moving on frictionless surface

So here if two boxes are considered as a system

then we have

$F = (m_1 + m_2) a$

$m_1 = 24 kg$

$m_2 = 62 kg$

$F = 36 N$

$36 = (24 + 62) a$

$a = 0.42 m/s^2$

Now since we know that both the boxes are moving together so force applied by first box on other box is given as

$F = ma$

$F = (62 \times 0.42)$

$F = 26.04 N$

6 0

3 years ago

Express the number in scientific notation: 4/100

ankoles [38]

Answer:

4*10^-2

Explanation:

for the scientific notation the first number must be between 1 and 10, so in this case it is 4. 4/100 is also equal to 0.04, and if we could the number of places before 4, there are two, therefore 4 times 10 to the power of -2

5 0

3 years ago

Any organism that has a skeletal sytem

Katena32 [7]

Vertebrate is the answer I think.

6 0

3 years ago

Read 2 more answers

The idea is to get as much EMF produced from the sprinter running through it. If you were the Olympic coach on a year when there

never [62]

Answer:

the greater the speed, the greater the electromotive force

* The metal pole must be parallel to the field

* you must keep the ball of the field

Explanation:

To determine the advice to the runners, let's use the Farad equation to and

fem = -N $\frac{ d \phi}{dt}$ = -N $\frac{ B A Cos \theta }{dt}$

how the runners are moving

fi = B l x

fem = -N B l v

therefore the advice we can give are:

* the greater the speed, the greater the electromotive force

* The metal pole must be parallel to the field

* you must keep the ball of the field

3 0

3 years ago