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3 years ago

What are the uses of oxygen?

Physics

2 answers:

almond37 [142]3 years ago

5 0

Respiration for plants (breathe it out) and animals (breathe it in)

Karo-lina-s [1.5K]3 years ago

4 0

The uses of oxygen are for respiration purposes in all animals and humans.

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A motor with a resistance of 320 is connected to a voltage source. Four amps of current flows

cricket20 [7]

Answer:

V = 1280 [V]

Explanation:

To solve this problem we must use ohm's law which tells us that the voltage is equal to the product of the resistance by the current.

Therefore we have:

V = I*R

where:

V = voltage [V] (Units of volts)

I = current = 4 [amp]

R = resistance = 320 [ohms]

V = 4*320

V = 1280 [V]

3 0

3 years ago

How are longitudinal and transverse waves alike? How are they different?

prohojiy [21]

SAME:
- They both transfer energy in waves
- They both have a frequency and period
- Both are mechanical waves and require a medium

DIFFERENT:
- Transverse waves move in a perpendicular direction
- Longitudinal waves move in a parallel direction

8 0

4 years ago

Read 2 more answers

What happens to atomic numbers as you follow a period across the periodic table

geniusboy [140]

Answer:

As you move across a period, the atomic mass increases because the atomic number also increases

Explanation:

When the atomic number increases, this means that there are more protons and neutrons that add to the atomic mass of an atom.

8 0

3 years ago

Which of these is a chemical of a pure substance

mafiozo [28]

Color? I'm going with color. Chem isn't my forte though

5 0

4 years ago

The shortest pipe in a particular organ is 1.23 m.

AVprozaik [17]

Answer:

The 9th harmonic is 1,010.67 Hz.

Explanation:

Given;

length of the pipe, L = 1.23 m

speed of sound at 0°C = 331.5 m/s

A pipe closed at one end is known as a closed pipe;

The wavelength of the sound for the first harmonic is calculated as;

L = Node ------ > Antinode

$L = \frac{\lambda }{4} \\\\\lambda = 4L$

First harmonic: $F_0 = \frac{V}{\lambda} = \frac{V}{4L}$

The wavelength of the sound for the first harmonic is calculated;

L = Node ----> Node + Node ------> Antinode

$L = \frac{\lambda}{2} + \frac{\lambda}{4} = \frac{2\lambda+\lambda}{4} = \frac{3\lambda}{4} \\\\\lambda = \frac{4 L}{3}$

Second harmonic: $F_1 = \frac{V}{\lambda} = \frac{3V}{4L}$

F₁ = 3F₀

The increment from F₀ to F₁ is 1 to 3; (odd number).

(1, 3, 5, 7, 9, 11, 13, 15, 17, 19..... n+2, where n is odd number)

The 9th harmonic = F₈

F₈ = 15F₀

$F_8= 17(F_0) = 15 (\frac{V}{4L} )\\\\F_8 = 15(\frac{331.5}{4\times 1.23} )\\\\F_8 = 1,010.67 \ Hz$

Therefore, the 9th harmonic is 1,010.67 Hz.

8 0

3 years ago