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Dmitry_Shevchenko [17]

3 years ago

11

George has $23 to spend on art supplies.He wants to buy markers,paper, and glue.If the total cost of the markers and paper is mo

re than $14, which inequality represents the dollar amount,p,George can spend on glue?

1 answer:

Lostsunrise [7]3 years ago

8 0

The inequality that would represent the amount that could be spent on glue, p is:

p <$9

You will determine this by subtracting 23 and 14 to get $9. If this is $9, that means you will spend less that that, because you will spend more that the $14 on the other supplies.

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Find the equation of the quadratic function with vertex (-2,18) passing through (-5,0)?

Sliva [168]

Answer:

$y-18=-2(x+2)^2$

Step-by-step explanation:

Equation of the Quadratic Function

The vertex form of the quadratic function has the following equation:

$y-k=a(x-h)^2$

Where (h, k) is the vertex of the parabola that results when plotting the function, and a is a coefficient different from zero.

It's been given the vertex of the parabola as (-2,18):

$y-18=a(x+2)^2$

Now substitute the point (-5,0) and find the value of a:

$0-18=a(-5+2)^2$

Operating:

$-18=a(-3)^2$

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3 years ago

Find the areas of the trapezoids.

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3 years ago

What is the product of all constants $k$ such that the quadratic $x^2 + kx +15$ can be factored in the form $(x+a)(x+b)$, where

Setler79 [48]

Answer:

$k=-16,k=-8,k=8,k=16$

Step-by-step explanation:

We are given quadratic equations as

$x^2+kx+15$

and it can be factored as

$=(x+a)(x+b)$

now, we can multiply factor term

$(x+a)(x+b)=x^2+(a+b)x+ab$

now, we can compare

$x^2+(a+b)x+ab=x^2+kx+15$

so, we get

$k=a+b$

$ab=15$

we are given that

'a' and 'b' are integers

so, we can find all possible factors

$15=(-1\times -15),(1\times 15)$

$15=(-3\times -5),(3\times 5)$

so, we can find k

At $(-1\times -15)$ :

$k=a+b$

we can plug values

$k=-1-15$

$k=-16$

At $(1\times 15)$ :

$k=a+b$

we can plug values

$k=1+15$

$k=16$

At $(-3\times -5)$ :

$k=a+b$

we can plug values

$k=-3-5$

$k=-8$

At $(3\times 5)$ :

$k=a+b$

we can plug values

$k=3+5$

$k=8$

So, values of k are

$k=-16,k=-8,k=8,k=16$

6 0

3 years ago