<span>0.38
You first calculate the total moles by dividing the grams by molecular weight:
45 g N2 / 28.02 g/mol = 1.6 mol N2
40 g Ar / 39.95 g/mol = 1.0 mol
Then you divide the moles of Ar by the total number of moles:
1.0 / (1.6 + 1.0) = 0.38 mol fraction</span>
Answer:- 544.5 mL of water need to be added.
Solution:- It is a dilution problem. The equation used for solving this type of problems is:
![M_1V_1=M_2V_2](https://tex.z-dn.net/?f=M_1V_1%3DM_2V_2)
where,
is initial molarity and
is the molarity after dilution. Similarly,
is the volume before dilution and
is the volume after dilution.
Let's plug in the values in the equation:
![1.25M(363mL)=0.50M(V_2)](https://tex.z-dn.net/?f=1.25M%28363mL%29%3D0.50M%28V_2%29)
![V_2=\frac{1.25M(363mL)}{0.50M}](https://tex.z-dn.net/?f=V_2%3D%5Cfrac%7B1.25M%28363mL%29%7D%7B0.50M%7D)
![V_2=907.5mL](https://tex.z-dn.net/?f=V_2%3D907.5mL)
Volume of water added = 907.5mL - 363mL = 544.5 mL
So, 544.5 mL of water are need to be added to the original solution for dilution.
I think it might be Selenium.
Answer:
They are called Myocyte.
Explanation:
A myocyte is said to be the type of cells that is found in muscle tissue. They are structurally long and also posses tubular cells that inhibits develop from myoblasts to form myogenesis process which are muscles.
Within a skeletal muscle fibre, there are many myocytes. arranged parallel to one another which gives the fibre a striated appearance. They are contractile parts of the muscle fibre.
Also, different forms of these myocytes has different qualities in our body muscles found in the cardiac, skeletal, and smooth muscle cells.