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vekshin1
3 years ago
11

Of their

Chemistry
1 answer:
pishuonlain [190]3 years ago
3 0

Answer:

the chemical equation of ethanol as fuel is

C2H5OH(l)+3 02(g)------2CO2(g)+3H2O(g)

the preparation process of ethanol from cassava is

cassava flour---liquification---saccharification---cooling---fermentation---distillation---ethanol

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Which are characteristics of a prokaryotic cell? Select three options.
Lostsunrise [7]

Answer:

Contains DNA, Contains Ribosomes, Lacks a nucleus

Explanation:

4 0
3 years ago
Read 2 more answers
What pressure (in atm) will a sample of o2 gas occupy at 100.0 ml, if o2 has a volume of 25.00 ml at 2.0 atm?
xeze [42]

Assuming that the O2 gas acts like an ideal gas, we find the following expression to be approximates of the behaviour of this gas:

<span>P V = n R T                   ---> 1</span>

where,

P = pressure exerted by the gas

V = volume occupied

n = number of moles

R = universal gas constant

T = absolute temperature

Further, we assume that the number of moles and the temperature are constant, hence reducing equation 1 into the form:

<span>P V = k                         ---> 2</span>

where k is a constant. Therefore we can equate two states:

P1 V1 = P2 V2

Since P1, V1 and V2 are given and we are to look for P2:

25 mL * 2 atm = 100 mL * P2

<span>P2 = 0.5 atm</span>

8 0
3 years ago
Read 2 more answers
Draw structures from the following names, and determine which compounds are optically active:(c) 1,2-dibromo-2-methylbutane
dolphi86 [110]

The given compound 1,2-dibromo-2-methylbutane is an optically active compound .

Because this compound does not have plane of symmetry (POS) and center  of symmetry (COS) i.e. does not have di-symmetry . And also forms non superimposable mirror image . the compound is optically active .

It has  chiral center.

Here , the chiral carbon is attached to the 4 distinct groups such as :  methyl , ethyl , bromine , bromomethane .

<h3>What is di-symmetry?</h3>

Di-symmetry is that which have no center of symmetry and plane of symmetry and alternate axis of symmetry .

<h3>Chiral center :</h3>

Have Sp3 hybridized center (4sigma bond ) .

4 distinct group  is attached to the chiral atom. form non -superimposable mirror image .

<h3>What is optical isomerism ?</h3>

Same molecular formula and same structural formula . also have same physical and chemical properties .

They differ in their behavior towards plane polarized light (ppl) .

Learn more about chiral center here:

brainly.com/question/9522537

#SPJ4

8 0
2 years ago
A flask contains 0.83molof neon gas at a temperature of 35°C. The pressure gauge indicates 0.37atm inside the flask. What is the
blsea [12.9K]

Answer:

V = 56.72 L

Explanation:

Given data:

Number of mole of neon gas = 0.83 mol

Temperature = 35°C

Pressure = 0.37 atm

Volume of gas = ?

Solution;

Temperature = 35°C  (35+273 =308K)

Formula:

PV = nRT

R = general gas constant = 0.0821 atm.L/mol.K

Now we will put the values in formula.

V = nRT/P

V = 0.83 mol ×0.0821 atm.L/mol.K ×308K / 0.37 atm

V = 20.99 L/  0.37

V = 56.72 L

6 0
4 years ago
Automobile airbags contain solid sodium azide, NaN 3 , that reacts to produce nitrogen gas when heated, thus inflating the bag.
Yuri [45]

<u>Answer:</u> The value of work for the system is -935.23 J

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of sodium azide = 16.5 g

Molar mass of sodium azide = 65 g/mol

Putting values in above equation, we get:

\text{Moles of sodium azide}=\frac{16.5g}{65g/mol}=0.254mol

The given chemical equation follows:

2NaN_3(s)\rightarrow 2Na(s)+3N_2(g)

By Stoichiometry of the reaction:

2 moles of sodium azide produces 3 moles of nitrogen gas

So, 0.254 moles of sodium azide will produce = \frac{3}{2}\times 0.254=0.381mol of nitrogen gas

To calculate volume of the gas given, we use the equation given by ideal gas, which follows:

PV=nRT

where,

P = pressure of the gas = 1.00 atm

V = Volume of the gas = ?

T = Temperature of the gas = 22^oC=[22+273]K=295K

R = Gas constant = 0.0821\text{ L. atm }mol^{-1}K^{-1}

n = number of moles of nitrogen gas = 0.381 moles

Putting values in above equation, we get:

1.00atm\times V=0.381mol\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 295K\\\\V=\frac{0.381\times 0.0821\times 295}{1.00}=9.23L

To calculate the work done for expansion, we use the equation:

W=-P\Delta V

We are given:

P = pressure of the system = 1atm=1.01325\times 10^5Pa     (Conversion factor:  1 atm = 101325 Pa)

\Delta V = change in volume = 9.23L=9.23\times 10^{-3}m^3     (Conversion factor:  1m^3=1000L )

Putting values in above equation, we get:

W=-1.01325\times 10^5Pa\times 9.23\times 10^{-3}m^3\\\\W=-935.23J

Hence, the value of work for the system is -935.23 J

7 0
4 years ago
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