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horrorfan [7]
3 years ago
11

A person throws a tennis ball 6 m/s straight up. How long does it take for it to come back to their hand?

Physics
2 answers:
Charra [1.4K]3 years ago
8 0

<u>Answer</u>

1.2245 s


<u>Explanation</u>

Using the Newton's law of linear motion,

v = u + gt


where v ⇒ Final velocity

            u ⇒ initial velocity,

             t ⇒ time to reach maximum height.

             g ⇒ acceleration due to gravity.

v = u + at

v = 0 m/s

g = -9.8 m/s²  (negative because the velocity is decreasing)

0 = 6 + -9.8t

9.8t = 6

t = 0.612244898 s

This is the time to reach maximum height. It will take the same time to come back to the hand.

so total time = 0.612244898 × 2

                      = 1.2245 s


Vlad1618 [11]3 years ago
6 0
Best Answer: BY v = u -gt =>0 = 6 - 9.8 x t =>t = 0.61 sec Thus time it take to come back to hand (T) = 2t = 1.22 sec Lol I hope this helps because I had funning helping you XD
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Answer: 16.3 seconds

Explanation: Given that the

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Let's first calculate the maximum height reached by using third equation of motion.

V^2 = U^2 - 2gH

Where V = final velocity and H = maximum height.

Since the toy is moving against the gravity, g will be negative.

At maximum height, V = 0

0 = 80^2 - 2 × 9.81 × H

6400 = 19.62H

H = 6400/19.62

H = 326.2

Let's us second equation of motion to find time.

H = Ut - 1/2gt^2

Let assume that the ball is dropped from the maximum height. Then,

U = 0. The equation will be reduced to

H = 1/2gt^2

326.2 = 1/2 × 9.81 × t^2

326.2 = 4.905t^2

t^2 = 326.2/4.905

t = sqrt( 66.5 )

t = 8.15 seconds

The time it will take for the rocket to return to ground level will be 2t.

That is, 2 × 8.15 = 16.3 seconds

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3 years ago
Which statement correctly compares the valence electrons for atoms of francium (Fr) and barium (Ba)?
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Answer:

Francium has fewer valence electrons, but they are in a higher energy level

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Particle motion in surface waves is __________ motion.
gulaghasi [49]
<h3>Answer;</h3>

<em>B.)neither longitudinal nor transverse</em>

<h3><u>Explanation;</u></h3>
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A horizontal spring with stiffness 0.4 N/m has a relaxed length of 11 cm (0.11 m). A mass of 21 grams (0.021 kg) is attached and
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Answer:

0.6983 m/s

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L₀ = Initial length = 11 cm = 0.11 m

L = Final length = 27 cm = 0.27 m

x = stretch in the spring = L - L₀ = 0.27 - 0.11 = 0.16 m

m = mass of the mass attached = 0.021 kg

v = speed of the mass

Using conservation of energy

Kinetic energy of mass = Spring potential energy

(0.5) m v² = (0.5) k x²

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Answer:

D. 2.5 Hz

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