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3 years ago

A person throws a tennis ball 6 m/s straight up. How long does it take for it to come back to their hand?

Physics

2 answers:

Charra [1.4K]3 years ago

8 0

<u>Answer</u>

1.2245 s

<u>Explanation</u>

Using the Newton's law of linear motion,

v = u + gt

where v ⇒ Final velocity

u ⇒ initial velocity,

t ⇒ time to reach maximum height.

g ⇒ acceleration due to gravity.

v = u + at

v = 0 m/s

g = -9.8 m/s² (negative because the velocity is decreasing)

0 = 6 + -9.8t

9.8t = 6

t = 0.612244898 s

This is the time to reach maximum height. It will take the same time to come back to the hand.

so total time = 0.612244898 × 2

= 1.2245 s

Vlad1618 [11]3 years ago

6 0

Best Answer: BY v = u -gt =>0 = 6 - 9.8 x t =>t = 0.61 sec Thus time it take to come back to hand (T) = 2t = 1.22 sec Lol I hope this helps because I had funning helping you XD

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3 years ago