Question

A person throws a tennis ball 6 m/s straight up. How long does it take for it to come back to their hand?

Answer 1

Answer

1.2245 s

Explanation

Using the Newton's law of linear motion,

v = u + gt

where v ⇒ Final velocity

            u ⇒ initial velocity,

             t ⇒ time to reach maximum height.

             g ⇒ acceleration due to gravity.

v = u + at

v = 0 m/s

g = -9.8 m/s²  (negative because the velocity is decreasing)

0 = 6 + -9.8t

9.8t = 6

t = 0.612244898 s

This is the time to reach maximum height. It will take the same time to come back to the hand.

so total time = 0.612244898 × 2

                      = 1.2245 s

Answer 2

Best Answer: BY v = u -gt =>0 = 6 - 9.8 x t =>t = 0.61 sec Thus time it take to come back to hand (T) = 2t = 1.22 sec Lol I hope this helps because I had funning helping you XD