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horrorfan [7]
3 years ago
11

A person throws a tennis ball 6 m/s straight up. How long does it take for it to come back to their hand?

Physics
2 answers:
Charra [1.4K]3 years ago
8 0

<u>Answer</u>

1.2245 s


<u>Explanation</u>

Using the Newton's law of linear motion,

v = u + gt


where v ⇒ Final velocity

            u ⇒ initial velocity,

             t ⇒ time to reach maximum height.

             g ⇒ acceleration due to gravity.

v = u + at

v = 0 m/s

g = -9.8 m/s²  (negative because the velocity is decreasing)

0 = 6 + -9.8t

9.8t = 6

t = 0.612244898 s

This is the time to reach maximum height. It will take the same time to come back to the hand.

so total time = 0.612244898 × 2

                      = 1.2245 s


Vlad1618 [11]3 years ago
6 0
Best Answer: BY v = u -gt =>0 = 6 - 9.8 x t =>t = 0.61 sec Thus time it take to come back to hand (T) = 2t = 1.22 sec Lol I hope this helps because I had funning helping you XD
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Explanation:

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Q= I*t = 140*0.760 = 106.C

(b) b. How far does an electron travel along the wire while the starter motor is on?(mm)

diameter of the conductor is 4.20 mm

But Radius= diameter/2= 4.20/2=

The radius of the conductor is 2.1mm, then if we convert to metre for consistency same then

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