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Alexxandr [17]
3 years ago
8

Which situation would create a field like the one shown here?

Physics
1 answer:
kiruha [24]3 years ago
7 0
D. Interaction between a magnetic South Pole and a copper bar
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A scientist carries out an experiment. How could she help other scientists judge the validity of her results?
NNADVOKAT [17]
One way to do it is she could right down the data that she got
4 0
3 years ago
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the base of a rectangular vessel measure 10m by 18cm. water is poured into a depth of 4cm. (a) what is the pressure on the base?
Alex787 [66]

Answer:

a) P =392.4[Pa]; b) F = 706.32[N]

Explanation:

With the input data of the problem we can calculate the area of the tank base

L = length = 10[m]

W = width = 18[cm] = 0.18[m]

A = W * L = 0.18*10

A = 1.8[m^2]

a)

Pressure can be calculated by knowing the density of the water and the height of the water column within the tank which is equal to h:

P = density * g *h

where:

density = 1000[kg/m^3]

g = gravity = 9.81[m/s^2]

h = heigth = 4[cm] = 0.04[m]

P = 1000*9.81*0.04

P = 392.4[Pa]

The force can be easily calculated knowing the relationship between pressure and force:

P = F/A

F = P*A

F = 392.4*1.8

F = 706.32[N]

4 0
3 years ago
If a fuse melts, does it create an open circuit, a closed circuit, or a short circuit?
Andrew [12]

Answer:

short circuit

7 0
3 years ago
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Which of the following is a correct formula of speed
satela [25.4K]

Answer:s= d/t

Explanation:

7 0
3 years ago
A student pulls a 2.0-kg object to the left with a force of 30 N, while another student is pulling against the object in the opp
alex41 [277]

Answer:

5 m/s2, left

Explanation:

We can solve the problem by applying Newton's second law of motion, which  states that:

\sum F=ma

where:

\sum F is the net force acting on an object

m is the mass of the object

a is its acceleration

In this problem, we have:

\sum F=30 N - 20 N = 10 N (to the left) is the net force on the object

m = 2.0 kg is the mass

So, the acceleration is:

a=\frac{\sum F}{m}=\frac{10}{2.0}=5.0 m/s^2

in the same direction as the force (left).

5 0
3 years ago
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