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xxMikexx [17]
4 years ago
15

Please, I need at least accurate answers for my Sound Knowledge Check for my Science class.

Chemistry
2 answers:
mrs_skeptik [129]4 years ago
8 0
Pretty sure it’s absorption
Alla [95]4 years ago
5 0

Answer:

1.A

2.A

3.C

4.C

5.B

6.A

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Fe + O2 + H₂O- & Fe2O3 + H₂O. balance por el método de tanteo​
AveGali [126]

Answer:

Fe + O2 + H₂O___ Fe2O3 + H₂O.

6Fe+302+H2O______2fe 203+H2O

5 0
3 years ago
What is the purpose of the stairstep pattern on the periodic table of the elements?
Mamont248 [21]

Answer: The bold staircase in the periodic table allows us to classify which elements are metalloids.

Explanation: Additionally, it acts like a "divider" that allows us to properly distinguish the metals from the non-metals in the periodic table.

                                          Add me as a friend!!!

                                                    (:  O_O :)

7 0
3 years ago
Helppppp with this pleasee
vazorg [7]

Answer:

A. 1, 2, 5

Explanation:

Count the number of Ns in the formula.

- Hope that helped! Please let me know if you need a further explanation.

3 0
3 years ago
You have 55 grams of glucose(C6H12O6). How many grams of oxygen do you have?
zubka84 [21]

Answer:

Mass of oxygen in glucose = 29.3g

Explanation:

Mass of glucose given is 55grams.

We are to find the mass of oxygen in this compound.

In the compound we have 6 atoms of oxygen.

Solution

To find the mass of oxygen in glucose, we calculate the formula mass of glucose. We now divide the formula mass of the oxygen atom with that of the glucose and multiply by the given mass to find the unkown mass.

Atomic mass of C = 12g

                           H = 1g

                           O = 16g

Formula mass of C₆H₁₂O₆ = {(12x6) + (1x12) + (16x6)} = 180

             Mass of O in glucose = \frac{6x16}{180}  x 55

                                                  = \frac{96}{180} x 55

                                                  = 0.53 x 55

            Mass of oxygen in glucose = 29.3g

8 0
3 years ago
Volume occupied 3.52x10^32 moluchles<br>of Mathane (CH4)<br>1) At STP​
Naddika [18.5K]

Answer:

volume = 13097674418.528dm³

Explanation:

n = (3.52)*10^32/(6.02)*10^23)

n = (584717607.97)

n = volume /molar volume

molar volume at stp = 22.4dm³

volume= 584717607.97 x 22.4

volume = 13097674418.528dm³

6 0
3 years ago
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