Question

2HClO4(aq)+Na2CO3(aq)→H2O(l)+CO2(g)+2NaClO4(aq) Express your answer as a complete ionic equation. Identify all of the phases in your answer. nothing Request Answer Part F Express your answer as a net ionic equation. Identify all of the phases in your answer. nothing Request Answer Part G NH4Cl(aq)+NaOH(aq)→H2O(l)+NH3(g)+NaCl(aq) Express your answer as a complete ionic equation. Identify all of the phases in your answer. nothing Request Answer Part H Express your answer as a net ionic equation. Identify all of the phases in your answer. nothing Request Answer Provide Feedback Correct. No additional followup.

Answer 1

Explanation:

Complete ionic equation : In complete ionic equation, all the substance that are strong electrolyte and present in an aqueous are represented in the form of ions.

Net ionic equation : In the net ionic equations, we are not include the spectator ions in the equations.  Only the species which are present in aqueous state dissociate.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

(a)

The balanced molecular equation will be,

$2HClO_4_{(aq)}+Na_2CO_3_{(aq)}\rightarrow H_2O_{(l)}+CO_2_{(g)}+2NaClO_4_{(aq)}$

The complete ionic equation in separated aqueous solution will be,

$2H^+_{(aq)}+2ClO_4^-_{(aq)}+2Na^+_{(aq)}+CO_3^{2-}_{(aq)}\rightarrow H_2O_{(l)}+CO_2_{(g)}+2Na^+_{(aq)}+2ClO_4^{-}_{(aq)}$

In this equation the species present are, $2Na^+\text{ and }2ClO_4^-$ are the spectator ions.

Hence, the net ionic equation contains specie is

$2H^+_{(aq)}+CO_3^{2-}_{(aq)}\rightarrow H_2O_{(l)}+CO_2_{(g)}$

(b)

The balanced molecular equation will be,

$NH_4Cl_{(aq)}+NaOH_{(aq)}\rightarrow H_2O_{(l)}+NH_3_{(g)}+NaCl_{(aq)}$

The complete ionic equation in separated aqueous solution will be,

$NH_4^+_{(aq)}+Cl^-_{(aq)}+Na^+_{(aq)}+OH^{-}_{(aq)}\rightarrow H_2O_{(l)}+NH_3_{(g)}+Na^+_{(aq)}+Cl^{-}_{(aq)}$

In this equation the species present are, $Na^+\text{ and }Cl^-$ are the spectator ions.

Hence, the net ionic equation contains specie is

$NH_4^+_{(aq)}+OH^{-}_{(aq)}\rightarrow H_2O_{(l)}+NH_3_{(g)}$