Answer:
To find time, use this: t = d/s ( time = distance ÷ speed)
Answer:
= 19
ΔG° of the reaction forming glucose 6-phosphate = -7295.06 J
ΔG° of the reaction under cellular conditions = 10817.46 J
Explanation:
Glucose 1-phosphate ⇄ Glucose 6-phosphate
Given that: at equilibrium, 95% glucose 6-phospate is present, that implies that we 5% for glucose 1-phosphate
So, the equilibrium constant can be calculated as:
![= \frac{[glucose-6-phosphate]}{[glucose-1-[phosphate]}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B%5Bglucose-6-phosphate%5D%7D%7B%5Bglucose-1-%5Bphosphate%5D%7D)
= 19
The formula for calculating ΔG° is shown below as:
ΔG° = - RTinK
ΔG° = - (8.314 Jmol⁻¹ k⁻¹ × 298 k × 1n(19))
ΔG° = 7295.05957 J
ΔG°≅ - 7295.06 J
b)
Given that; the concentration for glucose 1-phosphate = 1.090 x 10⁻² M
the concentration of glucose 6-phosphate is 1.395 x 10⁻⁴ M
Equilibrium constant can be calculated as:
0.01279816514 M
0.0127 M
ΔG° = - RTinK
ΔG° = -(8.314*298*In(0.0127)
ΔG° = 10817.45913 J
ΔG° = 10817.46 J
Answer:
liquid, solid, and gas
Explanation: It depends where the molecules are moving. When a solid the molecules are vibrating and are all together, compact, the molecules are also very slow. When a liquid the molecules are moving back and forth, up and down, and are less compact, but moving faster. When a gas, the molecules move everywhere very quickly, moving super fast.
<span>the ionization constant, Ka, for and indicator, HIn, is 1.0x10^-8. The color of the unionized form is red and the color of the ionized form is yellow. What is the color of the indicator in a solution whose pH is 4.6? (Hint: the color of an indicator can be estimated by considering the ratio of [HIn]/[In]. If the ratio is equal to or greater than 10, the color will bet hat of the unionized form. If the ratio is equal to or smaller than 0.1, the color will be that of the ionized form.
</span><span>Ka=[H+][A-]/[HA]
substitute for pH and find the value of A-/HA.
</span><span>
</span><span>so it'd just be 1x10^-8 divided by 4.6</span>
