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sergeinik [125]
3 years ago
5

When a piece of sodium carbonate reacts with dilute HCl, a gas X is produced. When gas X is passed through lime water then the s

olution turns milky and a white precipitate Y is formed a. Write the chemical formula of X, Y and (3)b. Write the chemical name of compound Y c. What is the nature of solution of sodium carbonate salt. Acidic salt or basic salt?
Chemistry
1 answer:
siniylev [52]3 years ago
7 0
Gas x would be carbon dioxide.

note/ acid + carbonate —> salt + water + carbon dioxide

the white precipitate would be calcium carbonate. CaCo₃

note/ this is a common eqn u need to remember.

X - CO₂ (carbón dioxide)
Y - CaCo₃ (calcium carbonate)

sodium carbonate is a basic salt
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CHEM HELP PLEASE
natka813 [3]

Answer:

90.2%

Explanation:

% yield = actual yield/ theoretical yield * 100%

% yield = (312/346)*100% = 90.2%

3 0
3 years ago
Calculate the molarity of an hcl solution if a 10.00 ml sample requires 25.24 ml of a 1.600 m naoh solution to be neutralized.
AlladinOne [14]

Answer:

The molarity of the HCl solution should be 4.04 M

Explanation:

<u>Step 1:</u> Data given

volume of HCl solution = 10.00 mL = 0.01 L

volume of a 1.6 M NaOH solution = 25.24 mL = 0.02524 L

<u>Step 2:</u> The balanced equation

HCl + NaOH → NaCL + H2O

Step 3: Calculate molarity of HCl

n1*C1*V1 = n2*C2*V2

Since the mole ratio for HCl and NaOH is 1:1 we can just write:

C1*V1 =C2*V2

⇒ with C1 : the molarity of HCl = TO BE DETERMINED

⇒ with V1 = the volume og HCl = 10 mL = 0.01 L

⇒ with C2 = The molarity of NaOH = 1.6 M

⇒ with V2 = volume of NaOH = 25.24 mL = 0.02524 L

C1 * 0.01 = 1.6 * 0.02524

C1 = (1.6*0.02524)/0.01

C1 = 4.04M

The molarity of the HCl solution should be 4.04 M

6 0
3 years ago
A
Aleksandr [31]

Answer:

D. Using a battery

3 0
3 years ago
Please help me out with this​
d1i1m1o1n [39]
Answer
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Explanation
4 0
2 years ago
A diver exhales a bubble with a volume of 250 mL at a pressure of 2.4 atm and a temperature of 15 °C. What is the volume of the
alexdok [17]

Answer : The volume of the bubble is, 625 mL

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 2.4 atm

P_2 = final pressure of gas = 1.0 atm

V_1 = initial volume of gas = 250 mL

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 15^oC=273+15=288K

T_2 = final temperature of gas = 27^oC=273+27=300K

Now put all the given values in the above equation, we get:

\frac{2.4atm\times 250mL}{288K}=\frac{1.0atm\times V_2}{300K}

V_2=625mL

Therefore, the volume of the bubble is, 625 mL

7 0
2 years ago
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