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Nonamiya [84]
3 years ago
13

Make the following conversion. 0.075 m = _____ cm 7.5 75 0.0075 0.00075

Chemistry
1 answer:
oee [108]3 years ago
5 0
7.5 is the answer. You have to move the decimal 2 places to the right.
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VA 19.75-g sample was heated by 12.35 calories. The specific heat of the sample is 0.125 cal/g°C. What was the initial temperatu
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Answer:

31.9 °C  

Explanation:

The formula for the heat q absorbed by an object is

q = mCΔT where ΔT = (T₂ - T₁)

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Calculations

(a) Calculate ΔT

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12.35 cal = 19.25 g × 0.125 cal°C⁻¹g⁻¹ × ΔT

12.35 = 2.406ΔT °C⁻¹  

ΔT  = 12.35/(2.406 °C⁻¹) = 5.13 °C

(b) Calculate T₂

ΔT = T₂ - T₁

T₁ = T₂ - ΔT = 37.0 °C - 5.13 °C = 31.9 °C

The original temperature was 31.9 °C.

 

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3 years ago
"Chilling" is most commonly practiced by:
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