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Harlamova29_29 [7]
3 years ago
13

What is a correct expression of the law of conservation mass

Chemistry
1 answer:
nekit [7.7K]3 years ago
5 0
Law of conservation of mass- The total mass after a chemical reaction is exactly the same as the mass before.
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Uranium-236 is _____. created by fusion reactions an unstable isotope of uranium created from four hydrogen atoms used in the H-
nata0808 [166]
<span>Uranium-236 is intermediate nuclei. created by fusion reactions an unstable isotope of uranium created from four hydrogen atoms used in the H-bomb.

Following is the reaction involved in above process:

</span>^{235}U+ ^{1}n →  ^{236}U→ ^{144}Ba + ^{89}Kr + 3 ^{1}n<span> + 177 MeV
</span>
Here, 
^{235}U = Fission material,
^{1}n = projectile,
^{236}U = intermediate nuclei,
^{144}Ba and ^{89}Kr = Fission product



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3 years ago
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Which one of the following would you expect to dissolve in water? limonene sucrose oil atmospheric oxygen none of the above
sdas [7]

-----------sucrose----------------

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3 years ago
_______ is an example for isotone. a)argon and carbon b) uranium and carbon c) carbon and boron d)sulphur and boron.​
slavikrds [6]

Isotones are nuclides that have the same neutron number but a different proton number. Therefore the answer is  C. boron and carbon.

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2 years ago
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Based on the three formulas shown, use one of them to solve for the purple yellow and red box and explain how you did it.
zysi [14]

P = 11.133 atm (purple)

T = -236.733 °C(yellow)

n = 0.174 mol(red)

<h3>Further explanation  </h3>

Some of the laws regarding gas, can apply to ideal gas (volume expansion does not occur when the gas is heated),:  

  • Boyle's law at constant T, P = 1 / V  
  • Charles's law, at constant P, V = T  
  • Avogadro's law, at constant P and T, V = n  

So that the three laws can be combined into a single gas equation, the ideal gas equation  

In general, the gas equation can be written  

\large {\boxed {\bold {PV = nRT}}}

where  

P = pressure, atm  

V = volume, liter  

n = number of moles  

R = gas constant = 0.08206 L.atm / mol K  

T = temperature, Kelvin  

To choose the formula used, we refer to the data provided

Because the data provided are temperature, pressure, volume and moles, than we use the formula PV = nRT

  • Purple box

T= 10 +273.15 = 373.15 K

V=5.5 L

n=2 mol

\tt P=\dfrac{nRT}{V}\\\\P=\dfrac{2\times 0.08205\times 373.15}{5.5}\\\\P=11.133~atm

  • Yellow box

V=8.3 L

P=1.8 atm

n=5 mol

\tt T=\dfrac{PV}{nR}\\\\T=\dfrac{1.8\times 8.3}{5\times 0.08205}\\\\T=36.42~K=-236.733^oC

  • Red box

T = 12 + 273.15 = 285.15 K

V=3.4 L

P=1.2 atm

\tt n=\dfrac{PV}{RT}\\\\n=\dfrac{1.2\times 3.4}{0.08205\times 285.15}\\\\n=0.174~mol

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3 years ago
Suppose you take a solution and add more solvent, so that the original mass of solvent is doubled. you take this new solution an
ser-zykov [4K]
The molarity remais the same
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