I hope I am right on this, but the answer is
Fe₂O₃ + 3CO --> 2Fe + 3CO₃
The statement "Although sulfuric acid is a strong electrolyte, an aqueous solution of H₂SO₄ contains more HSO₄⁻ ions than SO₄²⁻ ions is <u>True.</u> This is best explained by the fact that H₂SO₄ <u>is a diprotic acid where only the first hydrogen completely ionizes.</u>
Why?
H₂SO₄ is a diprotic acid. That means that it has <u>two hydrogen ions</u> to give to the solution. The two dissociation reactions are shown below:
H₂SO₄ + H₂O → HSO₄⁻ + H₃O⁺
HSO₄⁻ + H₂O ⇄ SO₄²⁻ + H₃O⁺
As the arrows show, the first dissociation is complete, meaning that all the sulfuric acid that is present initially is dissociated into HSO₄⁻ and H₃O⁺. However, the second dissociation is incomplete, and it's actually an equilibrium with an acid constant (Ka)of 1.2×10⁻².
That means that if the initial concentration of H₂SO₄ was 1M, the concentration of HSO₄⁻ is going to be 1M as well, but <u>the concentration of SO₄²⁻ is going to be much less than 1M</u>, according to the dissociation constant.
Have a nice day!
The components of a mixture maintain their original properties. True. That is because a mixture is not combined chemically.
Answer:
Lustrous is NOT a property of metal
Answer: The charge on peptide chain lys-lys-his-glu at pH 7 is +1.
Explanation: A peptide chain is the chain formed from the condensation of two amino acids releasing 
molecule and forming N-terminal(Nitrogen- end) and C-terminal(Carboxyl-end). The bonds formed are known as peptide bonds.
Here 4 amino acids join together forming a peptide chain
In this peptide chain N-terminal is from lysine (lys) and C-terminal is from Glutamic acid (Glu).
At pH=7,
- The carboxyl (-COOH) groups will be deprotonated that means they will not have H-atoms and have (-1) charge.
- The Amino (
) groups will be protonated that means they have H-atoms and have (+1) charge.
So, there are 3 amino groups present each having (+1) charge and 2 carboxyl groups each having (-1) charge.
Total charge on peptide chain = 
= +1
