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Doss [256]
2 years ago
12

A first-order reaction is 81omplete in 264s. A. What is the half-life for this reaction? b. How long will it take for the reacti

on to reach 95ompletion?
Chemistry
1 answer:
Arlecino [84]2 years ago
5 0

A first-order reaction is 81omplete in 264s.The half-life for this reaction (i) t 1/2 = =3.465×10 −3 s.to reach 95% Completion = 285 s.

To measure reaction rates, chemists initiate the reaction, measure the concentration of the reactant or product at different times as the reaction progresses,

For a 0-order response, the mathematical expression that may be employed to determine the half of life is: t1/2 = [R]0/2k. For a first-order reaction, the half of-existence is given by: t1/2 = zero.693/ok. For a 2d-order response, the method for the half-life of the response is: 1/okay[R]0

The 1/2-life of a response (t1/2), is the quantity of time needed for a reactant concentration to lower via half of compared to its initial awareness. Its software is used in chemistry and medicine to are expecting the awareness of a substance over time

Half of the lifestyles is the time required for exactly 1/2 of the entities to decay   50%.

Learn more about first order reaction here:-

#SPJ4

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Answer:

The general formula for an acid is HnX where H stands for hydrogen, n stands for the number of hydrogen ions, and X stands for the monatomic or polyatomic ions ( since those are negative charged ions, they are called anions).

Explanation:

The general formula for an acid is HnX) where H stands for hydrogen, n stands for the number of hydrogen ions, and X stands for the monatomic or polyatomic ions ( since those are negative charged ions, they are called anions).

An example is H2SO4, also called sulfuric acid

It shows that H2SO4 has 2 hydrogen atoms, so in the formula HnX n=2

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3 years ago
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Ivanshal [37]

Answer:

No, it is not feasible because the Gibbs free energy change is positive

Explanation:

∆Hreaction= (-602 KJ/mol) - (-348 KJ/mol) = -254 KJ/mol

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From;

∆G = ∆H - T∆S

∆G = 254 × 10^3 J/mol - [340K × (-8 J/Kmol)]

∆G = 2.57 × 10^5 J/mol

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Answer:

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The correct answer is:

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