Air resistance is ignored.
g = 9.8 m/s².
At maximum height, the vertical velocity is zero.
Let h = the maximum height reached.
Let u = the vertical launch velocity.
Because ot takes 5.0 seconds to reach maximum height, therefore
(u m/s) - (9.8 m/s²)*(5 s) = 0
u = 49 m/s
The maximum height reached is
h = (49 m/s)*(5 s) - (1/2)*(9.8 m/s²)*(5 s)²
= 122.5 m
Answer: 122.5 m
The person should start to slow down but if close enough or in the intersection go threw. Otherwise come to a complete stop until the light turns green again
Because gravity is constant
<span>the only force acting in free-fall is gravity which points downward at 9.8 m/s</span>
Answer:

Explanation:
Assuming no energy lost, according to the law of conservation of energy, the kinetic energy of the automobile becomes potential energy after the crash:

Here m is the automobile's mass, v is the speed of the car before impact, k is the "bumper" constant and x is the compression of the bumper due to the collision. Solving for v:
