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monitta
4 years ago
5

A 2.74 g coin, which has zero potential energy at the surface, is dropped into a 12.2 m well. After the coin comes to a stop in

the mud, what is its potential energy with respect to the surface?
Physics
1 answer:
nata0808 [166]4 years ago
8 0

Answer:

- 0.328J

Explanation:

POTENTIAL ENERGY = mgh

                                   = 0.00274 × 9.81×12.2  here 2.74g = 0.00274kg

                                   = 0.32792868 J

                                   = 0.328J

AS IT IS BELOW THE SURFACE HENCE MUST BE NEGATIVE

hence potential energy = - 0.328J

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A car moving at 30 m/s slows uniformly to a speed of 10 m/s in a time of 5 s. Determine 1. The acceleration of the car. 2. The d
ValentinkaMS [17]

Answer:

Explanation:

Initial velocity , u = 30 m/s

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1. Acceleration = v - u / t

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4 years ago
susan and joe push a table 18 meters down a hall by exerting a force of 200 newtons (n). what is the total amount of work done o
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3 0
2 years ago
Two Physics quick help
Free_Kalibri [48]

Answer:

21.3 V, 1.2 A

Explanation:

1.

These resistors are in series, so the net resistance is:

R = R₁ + R₂ + R₃

R = 20 + 30 + 45

R = 95

So the current is:

V = IR

45 = I (95)

I = 9/19

So the voltage drop across R₃ is:

V = IR

V = (9/19) (45)

V ≈ 21.3 V

2.

First, we need to find the equivalent resistance of R₂ and R₃, which are in parallel:

1/R₂₃ = 1/R₂ + 1/R₃

1/R₂₃ = 1/10 + 1/10

R₂₃ = 5

Now we find the overall resistance by adding the resistors in series:

R = R₁ + R₂₃ + R₄

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R = 25

So the current through R₁ is:

V = IR

30 = I (25)

I = 1.2 A

7 0
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