Question

A car is stopped at a red light. When the light turns green, the car accelerates until it reaches a final velocity of 45 m/s. It takes the car 12 s to reach this speed. How far does the car travel during this time.

Answer 1

Answer:

270 m

Explanation:

The motion of the car is a uniformly accelerated motion, so we can use the following suvat equation

$s=(\frac{u+v}{2})t$

where

s is the distance covered

u is the initial velocity

v is the final velocity

t is the time

For the car in this problem,

u = 0 (it starts from rest)

v = 45 m/s is the final velocity

t = 12 s is the time

Solving for s,

$s=(\frac{0+45}{2})(12)=270 m$