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gladu [14]
3 years ago
13

A car is stopped at a red light. When the light turns green, the car accelerates until it reaches a final velocity of 45 m/s. It

takes the car 12 s to reach this speed. How far does the car travel during this time.
Physics
1 answer:
hoa [83]3 years ago
4 0

Answer:

270 m

Explanation:

The motion of the car is a uniformly accelerated motion, so we can use the following suvat equation

s=(\frac{u+v}{2})t

where

s is the distance covered

u is the initial velocity

v is the final velocity

t is the time

For the car in this problem,

u = 0 (it starts from rest)

v = 45 m/s is the final velocity

t = 12 s is the time

Solving for s,

s=(\frac{0+45}{2})(12)=270 m

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Answers

The car's forward motion is opposed by the friction between the road and the tires and by the resistance of the air.

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Which way does the direction arrow always points
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The directions arrow<span> is </span>always<span> going the wrong </span>way<span>.</span>
8 0
3 years ago
w strong are you? Could you turn a moving car with just your own strength? No way! If a normal driver inputs about 50 N of force
malfutka [58]

The mechanical advantage of a simple machine is the measure of its amplified force gain.

The mechanical advantage  is defined as the force amplified by a machine to the force required to generate such output.

Mathematically\ mechanical\ advantage\ MA=\frac{F_{o}} {F_{i}}

F_{o} \ and\ F_{i} are the amplified force and applied force. We may also consider them as output and input force.          


In the given question, the force given to the steering wheel is 50 N.

The output force produced by the steering wheel is 3750 N.

Hence the mechanical advantage will be-

                               MA=\frac{F_{o}} {F_{i}}

                                       =\frac{3750\ N}{50\ N}

                                       =75      [ans]

3 0
3 years ago
A cord is used to vertically lower an initially stationary block of mass M = 3.6 kg at a constant downward acceleration of g/7.
dalvyx [7]

Answer:

(a) W_c=127.008 J

(b) W_g=148.176 J

(c) K.E. = 21.168 J

(d) v=3.4293m.s^{-1}

Explanation:

Given:

  • mass of a block, M = 3.6 kg
  • initial velocity of the block, u=0 m.s^{-1}
  • constant downward acceleration, a_d= \frac{g}{7}

\Rightarrow That a constant upward acceleration of \frac{6g}{7} is applied in the presence of gravity.

∴a=- \frac{6g}{7}

  • height through which the block falls, d = 4.2 m

(a)

Force by the cord on the block,

F_c= M\times a

F_c=3.6\times (-6)\times\frac{9.8}{7}

F_c=-30.24 N

∴Work by the cord on the block,

W_c= F_c\times d

W_c= -30.24\times 4.2

We take -ve sign because the direction of force and the displacement are opposite to each other.

W_c=-127.008 J

(b)

Force on the block due to gravity:

F_g= M.g

∵the gravity is naturally a constant and we cannot change it

F_g=3.6\times 9.8

F_g=35.28 N

∴Work by the gravity on the block,

W_g=F_g\times d

W_g=35.28\times 4.2

W_g=148.176 J

(c)

Kinetic energy of the block will be equal to the net work done i.e. sum of the two works.

mathematically:

K.E.= W_g+W_c

K.E.=148.176-127.008

K.E. = 21.168 J

(d)

From the equation of motion:

v^2=u^2+2a_d\times d

putting the respective values:

v=\sqrt{0^2+2\times \frac{9.8}{7}\times 4.2 }

v=3.4293m.s^{-1} is the speed when the block has fallen 4.2 meters.

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3 years ago
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shusha [124]

The angle of reflection is  equal to angle of incidence so the angle of reflection is also 32°.

6 0
3 years ago
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