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3 years ago

A 24 kg rock is resting on the floor. How much potential energy does it have?

1 answer:

7 0

Relative to the floor it's resting on, its height is zero,
so its potential energy is zero.

Relative to the next floor down, its height could be
three or four meters, and it could have plenty of
potential energy ... if you cut out a circle in the floor
all around the rock, and let it fall to next floor down,
it could really do some damage. Look out below ! !

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A charged particle enters into a uniform magnetic field such that its velocity vector is perpendicular to the magnetic field vec

Ugo [173]

Answer:

a circular path

Explanation:

In a magnetism field if a charged particle having a charge of magnitude '' enters such that its velocity vector V is 90° to the direction of the magnetic field "B'', then it will experience a force, called Lorentz force F

$F = V\times B$

According to the property of cross-product, the Lorentz force (F) acting on the particle will be perpendicular to the instantaneous position of the particle, making the path of the particle to be a circular path.

3 0

3 years ago

Two ice skaters approach each other at right angles. Skater A has a mass of 32.7 kg and travels in the x direction at 2.3 m/s. S

UkoKoshka [18]

Answer:

Final speed, v = 1.25 m/s

Explanation:

Given that,

Mass of skater A, $m_A=32.7\ kg$

Initial speed of skater A, $u_A=2.3i\ m/s$ (x axis)

Mass of skater B, $m_B=93.3\ kg$

Initial speed of skater B, $u_B=1.51j\ m/s$ (y axis)

It is mentioned that the two skaters collide and cling together. It is case of inelastic collision in which momentum remains conserved. Let V is the final speed of the couple. It is given by :

$m_Au_A+m_Bu_B=(m_A+m_B)V$

$32.7\times 2.3i+93.3\times 1.51j=(32.7+93.3)V$

$V=\dfrac{75.21i+140.88j}{126}$

$V=(0.59i+1.11j)\ m/s$

$|V|=1.25\ m/s$

So, the final speed of the couple is 1.25 m/s. Hence, this is the required solution.

3 0

3 years ago

Graph are pictorical representations of

inn [45]

Answer:

Graphs are pictorial representations of relationships.

6 0

3 years ago

Read 2 more answers

Using energy considerations, calculate the average force (in N) a 67.0 kg sprinter exerts backward on the track to accelerate fr

Illusion [34]

Answer:

$F_{sprinter}=110.4N$

Explanation:

Given data

Mass m=67.0 kg

Final Speed vf=8.00 m/s

Initial Speed vi=2.00 m/s

Distance d=25.0 m

Force F=30.0 N

From work-energy theorem we know that the work done equals the change in kinetic energy

W=ΔK=Kf-Ki=1/2mvf²-1/2mvi²

And

$W=F_{total}.d$

$W=1/2mv_{f}^2-1/2mv_{i}^2\\F_{total}=\frac{1/2mv_{f}^2-1/2mv_{i}^2}{d} \\F_{total}=\frac{1/2(67.0kg)(8.00m/s)^2-1/2(67.0kg)(2.00m/s)^2}{25.0m} \\F_{total}=80.4N$

and we know that the force the sprinter exerted Fsprinter the force of the headwind Fwind=30.0N

$F_{sprinter}=F_{total}+F_{wind}\\F_{sprinter}=80.4N+30N\\F_{sprinter}=110.4N$

7 0

3 years ago

Read 2 more answers

What is the resultant of the vectors shown?

ad-work [718]

Answer:

Option B

Explanation:

Option A is the wrong answer because the horizontal vector is in the opposite direction.

Option C is the wrong answer as the horizontal vector is in the opposite direction and all the vectors are connected head to tail [of the arrows] [Triangle law of vector addition]

Option D is the wrong answer as the horizontal vector is in the opposite direction.

5 0

2 years ago