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tangare [24]
3 years ago
15

Imagine two fixed charges on the x axis. Charge one is +q and is located to the left of charge two which is equal to -4q. Where

on the axis (other than at an infinite distance) is there a point at which their net electric field is zero? a) Between the chargesb) To the left of the chargesc) To the right of the charg
Physics
1 answer:
givi [52]3 years ago
7 0

Answer: B)To the left of the charges.

Explanation: between the charges the electric field will not cancel but will be added since electric field lines from both charges point in the same direction. To the right of the charge the -4q will take over as it’s strength overcomes the strength of the +q charge. At this point the magnitude of +q will never reach a magnitude strong enough to cancel the -4q. To the left, it is further away from -4q and is closer to +q and electric field lines point in different direction

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The large blade of a helicopter is rotating in a horizontal circle. The length of the blade is 7.17 m, measured from its tip to
gayaneshka [121]

Answer:

1.789

Explanation:

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recall that tangential velocity can be related to angular velocity, ω by the following relationship:

V = rω, where V is the tangential velocity, ω is angular velocity and r = radius.

rearranging, we get

ω = V/r

We also know that at any point in the rotation, even though the tangential velocity at 7.17m radius (V₁)   will be different from the tangential velocity at 4.01m radius  (V₂), their angular velocity will be the same, hence we can equate:

ω₁ = ω₂, or

V₁/r₁ = V₂/r₂ (rearranging)

V₁/V₂ = r₁/r₂ -----(eq 1)

We also know that centripetal acceleration can be expressed in terms of tangential velocity and radius, i.e

a =V²/r

to find the ratio of the centripetal acceleration at the tip and at r=4.01m

a₁/a₂ = (V₁²/r₁)   / ( V₂² / r₂)   (rearranging & simplify)

=  (V₁/V₂)² (r₂ / r₁)   (substituting eq1 into equation)

=  (r₁/r₂)²(r₂ / r₁)  (simplifying)

= (r₁/r₂)    (substituting r₁=7.17 and r₂=4.01)

= 7.17 / 4.01

= 1.789

7 0
4 years ago
3. How does the centripetal force change when
OLga [1]

Answer:

The centripetal force increases.

Explanation:

Centripetal force is given by F_c=ma_c; where a_c=\frac{v^2}{r}.

Given these two equations, we can rewrite the formula for centripetal force as:

F_c=m\frac{v^2}{r}

As shown, radius is in the denominator, thus, a smaller radius would lead to a larger centripetal force.

7 0
3 years ago
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andrezito [222]
Concentration involves the relative amounts of solvent and solute in a solution, when strength is related to the extent to which a substance dissociates :))
i hope this is helpful 
have a nice day 
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3 years ago
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IRISSAK [1]

Answer:

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