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tangare [24]
3 years ago
15

Imagine two fixed charges on the x axis. Charge one is +q and is located to the left of charge two which is equal to -4q. Where

on the axis (other than at an infinite distance) is there a point at which their net electric field is zero? a) Between the chargesb) To the left of the chargesc) To the right of the charg
Physics
1 answer:
givi [52]3 years ago
7 0

Answer: B)To the left of the charges.

Explanation: between the charges the electric field will not cancel but will be added since electric field lines from both charges point in the same direction. To the right of the charge the -4q will take over as it’s strength overcomes the strength of the +q charge. At this point the magnitude of +q will never reach a magnitude strong enough to cancel the -4q. To the left, it is further away from -4q and is closer to +q and electric field lines point in different direction

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guys be careful noblepenguin is getting people banned he took all my brainliest he has to be stopped has a bot a be careful Kati
Julli [10]

Answer:

K thanks for letting everyone know!

Explanation:

7 0
3 years ago
Read 2 more answers
A 1000-kg car is driving toward the north along a straight horizontal road at a speed of 20.0 m/s. The driver applies the brakes
Nitella [24]

Answer:

The value of F= - 830 N

Since the force is negative, it implies direction of the force applied was due south.

Explanation:

Given data:

Mass = 1000-kg

Distance, d = 240 m

Initial velocity, v1 = 20.0 m/s

Final velocity, v2 = 0 (since the car came to rest after brake was applied)

v2²= v1² + 2ad (using one of the equation of motion)

0=  20² + (2 x a x  240)

0= 400 + 480 a

a = - 400/480

a = - 0.83 m/s²

Then, imputing the value of a into

F = ma

F = 1000 kg x ( - 0.83 m/s²)

F= - 830 N

The car was driving toward the north, and since the force is negative, it implies direction of the force applied was due south.

3 0
3 years ago
Chet believes that electric fields can impact objects only when the objects are in direct contact. Tonya disagrees with Chet. Wh
Murljashka [212]

B because it is the only evidence that displays an effect from the field without contact

3 0
3 years ago
Please help.
ddd [48]
This is a tough one.
In A, B, and C, there are various routes to get from one end to the other end through 2 or 3 capacitors.
D is the only configuration where it's possible to get from one end to the other through only 1 of them.
I'm not totally confident, but I think D is the one that's not like the others.
4 0
3 years ago
Can someone help me?!!!!!
kramer

Answer:

Parabola

Explanation:

The motion of a projectile consists of two independent motions:

- A uniform motion along the horizontal (x) direction, with constant velocity v_x. In fact, there are no forces acting along this direction (if we neglect air resistance), so the acceleration is zero and the velocity is constant

- An uniformly accelerated motion along the vertical (y) direction, with constant acceleration g=9.8 m/s^2 downward (acceleration due to gravity). This acceleration is due to the force of gravity that pulls the projectile downward.

The composition of these two motions gives a parabolic trajectory. In fact, the equations of the motion along the two directions are:

x(t) = v_x t (1)

y(t) = h + v_y t - \frac{1}{2}gt^2 (2)

Solving for t in eq.(1),

t=\frac{x}{v_x}

and substituting into (2)

y(t) = h + \frac{v_y}{v_x}x - \frac{1}{2}g(\frac{x}{v_x})^2

which is the equation of a parabola.

5 0
3 years ago
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