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tangare [24]
3 years ago
15

Imagine two fixed charges on the x axis. Charge one is +q and is located to the left of charge two which is equal to -4q. Where

on the axis (other than at an infinite distance) is there a point at which their net electric field is zero? a) Between the chargesb) To the left of the chargesc) To the right of the charg
Physics
1 answer:
givi [52]3 years ago
7 0

Answer: B)To the left of the charges.

Explanation: between the charges the electric field will not cancel but will be added since electric field lines from both charges point in the same direction. To the right of the charge the -4q will take over as it’s strength overcomes the strength of the +q charge. At this point the magnitude of +q will never reach a magnitude strong enough to cancel the -4q. To the left, it is further away from -4q and is closer to +q and electric field lines point in different direction

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A point charge q1=2.0μC is located on the positive y axis at y=0.30m, and an identical charge q2 is at the origin. Find the magn
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(A) 0.279N at angle 38.02°

(B) 0.701N

(C) 14.19°

Explanation:

(A) The net force on q3 is given as:

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Fx is the x component of the force

Fy is the y component of the force

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Fy = -F(2, 3)cosx - F(2, 3)cos90 = -F(2, 3)cosx

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Using SOHCAHTOA to find x,

sinx = 0.4/0.5

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F = kqQ/r²

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F(2, 3) = 0.45N

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Fx = -0.288cos36.87 + 0.45

Fx = 0.22N

Fy = 0.288cos53.13

Fy = 0.172N

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The magnitude of the force will be

F(mag) = √(0.22² + 0.172²)

F(mag) = 0.279N

The direction of the force makes will be

tanθ = Fy/Fx

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(B) q2 = - 2.0 * 10^(-6)

This implies that:

F(2,3) = (k*q2*q3) / r²

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