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6. The temperature of a mass of tin increases from 24.0 degrees C to 34.0 degrees C when 250 J of thermal energy are added. Calc

irina [24]

Answer:

110 g

Explanation:

q = mCΔT

where q is heat, m is mass, C is specific heat capacity, and ΔT is change in temperature.

Given q = 250 J, C = 0.228 J/g/°C, and ΔT = 10.0 °C:

250 J = m (0.228 J/g/°C) (10.0 °C)

m = 110 g

6 0

3 years ago

A charge −1.3 × 10−5 C is fixed on the x-axis at 7 m, and a charge 1 × 10−5 C is fixed on the y-axis at 4 m. Calculate the magni

wariber [46]

Answer:

6104 N/C.

Explanation:

Given:

k = 8.99 × 10^9 Nm2/C^2

Qx = 1.3 × 10^-5 C

rx = 7 m

Qy = 1 × 10−5 C

ry = 4 m

E = F/Q

= kQ/r^2

Ex = (8.99 × 10^9 × 1.3 × 10^−5) ÷ 7^2

= 2385.1 N/C.

Ey = (8.99 × 10^9 × 1.0 × 10^−5) ÷ 4^2

= 5618.75 N/C

Eo = sqrt(Ex^2 + Ey^2)

= sqrt(3.157 × 10^7 + 5.69 × 10^6)

= 6104 N/C.

5 0

3 years ago

The block shown above has a mass of 105 g.<br> What is the density of the block? SC.8.P.8.3

zaharov [31]

The density of the block is 1.25 cm³

The correct answer to the question is Option B. 1.25 cm³

To solve this question, we'll begin by calculating the volume of the block. This can be obtained as follow:

Length = 7 cm

Height = 4 cm

Width = 3 cm

<h3>Volume =? </h3>

Volume = Length × Width × Height

Volume = 7 × 3 × 4

<h3>Volume = 84 cm³</h3>

Thus, the volume of the block is 84 cm³

Finally, we shall determine the density of the block. This can be obtained as follow:

Density is defined as mass per unit volume i.e

$Density = \frac{mass}{volume} \\\\$

Mass of block = 105 g

Volume of block = 84 cm³

<h3>Density of block =? </h3>

$Density = \frac{mass}{volume}\\\\Density = \frac{105}{84}\\\\$

<h3>Density of block = 1.25 cm³</h3>

Therefore, the density of the block is 1.25 cm³.

Hence, Option B. 1.25 cm³ gives the correct answer to the question.

Learn more: brainly.com/question/2040396?referrer=searchResults

4 0

2 years ago

A baseball is thrown directly upward from ground level with a velocity of +15 m/s. What are the two times when the ball is 10 m

erastovalidia [21]

Answer:

time is 0.5660 s

and time is - 3.62431 s

Explanation:

velocity u = 15 m/s

height s = 10 m

acceleration due to gravity g = –9.8 m/s²

to find out

time

solution

we will apply here distance equation that is

s = ut - 1/2× gt² ...........1

here put all these value and get time t

here s is height and g is -9.8

so

s = ut - 1/2× gt²

10 = 15t - 1/2× (-9.8)t²

10 = 15t + 4.9t²

solve it we get t

t = 0.56630 and -3.62431

so time is 0.5660 s

and time is - 3.62431 s

8 0

4 years ago

How long is a string under 240 N of tension whose mass is 0.086 kg if a wave travels through it at a speed of 12 m/s?

Darina [25.2K]

Answer:

The length of the string is 0.051 meters

Explanation:

It is given that,

Tension in the string, T = 240 N

Mass of the string, m = 0.086 kg

Speed of the wave, v = 12 m/s

The speed of the wave on the string is given by :

$v=\sqrt{\dfrac{T}{M}}$

M is the mass per unit length of the string i.e. M = m/l.......(1)

So, $M=\dfrac{T}{v^2}$

$M=\dfrac{240\ N}{(12\ m/s)^2}$

M = 1.67 kg/m

The length of the string can be calculated using equation (1) :

$l=\dfrac{m}{M}$

$l=\dfrac{0.086\ kg}{1.67\ kg/m}$

l = 0.051 m

So, the length of the string is 0.051 meters. Hence, this is the required solution.

6 0

3 years ago