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Svetlanka [38]
3 years ago
9

What's the difference between Uniform magnetic field and Non-uniform magnetic field?

Physics
1 answer:
Galina-37 [17]3 years ago
4 0
Magnetic field is the magnetic effect of electric currents and magnetic materials. The magnetic field at any given point specified by both direction and a magnitude. So uniform magnetic field has equal amount of force or magnetic force in both side of the object while the non uniform magnetic field has one of the object exert more than the other 
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06
Novosadov [1.4K]

D

Explanation:

The are the same but difference

8 0
3 years ago
A ____ is a non solid state of matter in which the atoms and molecules are free to move past each other, as in a gas or liquid.
Licemer1 [7]
The answer is GAS. In a gas, the particles are in a completely random motion in any direction. And it is not solid. Hope I helped. Good luck
6 0
3 years ago
Read 2 more answers
Can a average velocity be zero.Why? ​
marishachu [46]

<u>Answer:</u>

Yes

<u>Explanation:</u>

Average velocity is the ratio of total displacement and time taken for that displacement:

average \space\ velocity = \frac{displacement}{time}

This means if displacement is zero, then average velocity will also be zero.

Displacement is zero when an object moves some distance in one direction, and then moves the same distance but in the opposite direction.

∴ As it is possible for displacement to be zero, it is also possible for average velocity to be zero.

4 0
2 years ago
57.9 g of gold has a volume of 3 cm³ what is the density of gold in g/ centimeters cubed
Grace [21]
D=m÷v

so density would be 57.9 ÷ 3 = 19.3 g/cm³
7 0
3 years ago
Read 2 more answers
Simplified. The absorption spectra of ions have been used to identify the presence of the elements in the atmospheres of the sun
Nookie1986 [14]

Answer:

The answer is "3.83 \times 10^9 \ m"

Explanation:

Z=2, so the equation is E= \frac{-4B}{n^2}

Calculate the value for E when:  

n=2 and n=9

The energy is the difference in transformation, name the energy delta E Deduct these two energies  

In this transition, the wavelength of the photon emitted is:

\Delta E=2.18 \times  10^{-18} ( \frac{1}{4}- \frac{1}{81})

\lambda = \frac{h c}{\Delta E}

h ( Planck's\  constant) = 6.62 \times  10^{(-34)} \ Js \\\\ speed \ of \ light = 3 \times 10^{8} \ \frac{m}{s}\\\\= \frac{6.62 \times 10^{(-34)} \times 3 \times 10^ {8}}{2.18 \times  10^{-18}} (\frac{1}{4}- \frac{1}{81}) \\\\=3.83 \times 10^9 \ m\\\\

6 0
3 years ago
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