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Alenkinab [10]
4 years ago
14

At a given point in its orbit, the moon is 2.4 x 10^5 miles from earth. How long does it take light from a source on earth to re

ach a reflector on the moon and then return to earth? (speed of light is 3.0 x 10^8 m/s)
Physics
2 answers:
Mice21 [21]4 years ago
8 0

Answer:

Total time= 2.56 s

Explanation:

Given that

Distance = 2.4\times 10^5\ miles

So distance = 386242560 m

Velocity of light

C= 3\times 10^8\ m/s

We know that

Distance = velocity x time

Now by putting then values

time=\frac{386242560}{3\times 10^8}

t=1.28 s

So the total time = 2 x 1.28

total time= 2.56 s

Naddik [55]4 years ago
8 0

Explanation:

Given that,

Distance between moon and earth, d=2.4\times 10^5\ miles

1 mile = 1609.34 meters

d=386241600\ m

Speed of light, c=3\times 10^8\ m/s

We need to find the time taken by the light from a source on earth to reach a reflector on the moon and then return to earth. Time is given by :

t=\dfrac{d}{c}

t=\dfrac{386241600\ m}{3\times 10^8\ m/s}      

t = 1.28 seconds

Hence, this is the required solution.

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An object with a mass of 32 kg has an initial energy of 500). At the end of the experimentthe velocity of the object is recorded
Alik [6]

Answer:

 F = 1.68 N

Explanation:

Let's solve this exercise in parts.

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     Em₀ = K = ½ m v₀²

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     v₀ = 5.59 m / s

now with kinematics we can find a space

      v² = v₀² - 2 a x

the negative sign is because the body is stopping

       a =( \frac{v_{o}^{2} - v^{2}   }{2x} )  

let's calculate

       a = (5.59² - 5.1²) / 2 50  

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