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Alenkinab [10]
4 years ago
14

At a given point in its orbit, the moon is 2.4 x 10^5 miles from earth. How long does it take light from a source on earth to re

ach a reflector on the moon and then return to earth? (speed of light is 3.0 x 10^8 m/s)
Physics
2 answers:
Mice21 [21]4 years ago
8 0

Answer:

Total time= 2.56 s

Explanation:

Given that

Distance = 2.4\times 10^5\ miles

So distance = 386242560 m

Velocity of light

C= 3\times 10^8\ m/s

We know that

Distance = velocity x time

Now by putting then values

time=\frac{386242560}{3\times 10^8}

t=1.28 s

So the total time = 2 x 1.28

total time= 2.56 s

Naddik [55]4 years ago
8 0

Explanation:

Given that,

Distance between moon and earth, d=2.4\times 10^5\ miles

1 mile = 1609.34 meters

d=386241600\ m

Speed of light, c=3\times 10^8\ m/s

We need to find the time taken by the light from a source on earth to reach a reflector on the moon and then return to earth. Time is given by :

t=\dfrac{d}{c}

t=\dfrac{386241600\ m}{3\times 10^8\ m/s}      

t = 1.28 seconds

Hence, this is the required solution.

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shannon dropped his ICP textbook. how fast was it going after 3 seconds? how far did it fall? please guys help mee quickly pleas
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¡Hola!

For this problem, first, lets recabe information:

v = 0 m/s

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g = 9,82 m/s²

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First, for calculate the final velocity:

v' = v + g * t

v' = 0 m/s + 9,82 m/s² * 3 s

v' = 29,46 m/s \leftarrow \boxed{\text{Velocity} }

Now, for calculate how far did it fall:

d = v * t + g * t^2 / 2

Like v = 0 m/s, we can simplificate equation:

d = g * t^2 / 2

d = 9,82 m/s² * (3 s)^2 / 2

d = 9,82 m/s² * 9 s² / 2

d = 88,38 m / 2

d = 44.19  m \leftarrow \boxed{\text{Distance} }

¡Buena suerte!

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