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artcher [175]
3 years ago
9

The star Rho1 Cancri is 57 light-years from the earth and has a mass 0.85 times that of our sun. A planet has been detected in a

circular orbit around Rho1 Cancri with an orbital radius equal to 0.11 times the radius of the earth's orbit around the sun. What are (a)the orbital speed and (b)the orbital period of the planet of Rho1 Cancri
Physics
1 answer:
vodka [1.7K]3 years ago
8 0

Answer:

82780.42123 m/s

14.45 days

Explanation:

m = Mass of the planet

M = Mass of the star = 0.85\times 1.989\times 10^{30}\ kg

r = Radius of orbit of planet = 0.11\times 149.6\times 10^{9}\ m

v = Orbital speed

The kinetic and potential energy balance is given by

\frac{GMm}{r^2}=\frac{mv^2}{r}\\\Rightarrow v=\sqrt{\frac{Gm}{r}}\\\Rightarrow v=\sqrt{\frac{6.67\times 10^{-11}\times 0.85\times 1.989\times 10^{30}}{0.11\times 149.6\times 10^{9}}}\\\Rightarrow v=82780.42123\ m/s

The orbital speed of the star is 82780.42123 m/s

The orbital period is given by

t=\frac{2\pi r}{v}\\\Rightarrow t=\frac{2\pi \times 0.11\times 149.6\times 10^{9}}{82780.42123}\\\Rightarrow t=1249040.48419\ seconds=\frac{1249040.48419}{24\times 60\times 60}=14.45\ days

The orbital period is 14.45 days

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Viktor [21]

Answer:

A) Φ = 0 , B)  T = 7.76 s

Explanation:

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B) the period is defined by time or when the movement begins to repeat itself

So that the sine function is repeated when the angle passes 2pi

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If we are at a fixed point x = 0

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Let's calculate

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3 years ago
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The trickiest part of this problem was making sure where the Yakima Valley is.
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Just for a place to work with, I picked the Yakima Valley Junior College, at the
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2 years ago
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Brums [2.3K]
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7 0
2 years ago
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