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2 years ago

What is newtons first,second, and third law?

1 answer:

6 0

Newton's first law states that every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force.

Newton's second law of motion pertains to the behavior of objects for which all existing forces are not balanced. .

Newton's third law: All forces in the universe occur in equal but oppositely directed pairs.

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One of the 64.3-cm-long strings of an ordinary guitar is tuned to produce the note LaTeX: B_3B 3 (frequency 245 Hz) when vibrati

Phoenix [80]

Answer:

v = 315 m/s

Explanation:

given,

length of the string = 64.3 cm

frequency at fundamental mode = 245 Hz

speed of sound = 345 m/s

speed of the transverse waves = ?

here

wavelength = twice length of string

λ = 2 L

λ = 2 × 64.3

λ = 128.6 cm = 1.286 m

using formula

v = ν λ

v = 245 × 1.286

v = 315.07 m/s

Hence, the speed of the transverse wave on the string will be equal to v = 315 m/s

8 0

3 years ago

Snowflakes begin to form when water in the atmosphere freezes it causes the water molecules to bond into a hexagonal shape. Is t

jarptica [38.1K]

Answer:

Yes! This sentence is correct.

Explanation:

So the complete question along with options is:

Q. Snowflakes begin to form when water in the atmosphere freezes it causes the water molecules to bond into a hexagonal shape.

a) no change

b) freezes, causing

c) freezes, it causes

d) freezes, this causes.

The coorect option is c.

7 0

2 years ago

The free-fall acceleration at the surface of planet 1 is 22 m/s^2. The radius and the mass of planet 2 are twice those of planet

algol13

Answer:

g₂ = 11 m/s²

Explanation:

The value of free-fall acceleration on the surface of a planet is given by the following formula:

$g = \frac{Gm}{r^2}$

where,

g = free-fall acceleration

G = Universal Gravitational Constant

m = mass of the planet

r = radius of planet

FOR PLANET 1:

$g_1 = \frac{Gm_1}{r_1^2}\\\\\frac{Gm_1}{r_1^2} = 22 m/s^2$ --------------------- equation (1)

FOR PLANET 2:

$g_2 = \frac{Gm_2}{r_2^2}\\\\g_2 = \frac{G(2m_1)}{(2r_1)^2}\\\\g_2 = \frac{1}{2}\frac{Gm_1}{r_1^2}\\\\$

using equation (1):

$g_2 = \frac{g_1}{2}\\\\g_2 = \frac{22\ m/s^2}{2}$

8 0

2 years ago

our friend is constructing a balancing display for an art project. She has one rock on the left (ms=2.25 kgms=2.25 kg) and three

Licemer1 [7]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The torque produced by the pile of rocks is $\tau = 35.63\ N \cdot m$

The distance of the single for equilibrium to occur is $r_s =1.62 \ m$

Explanation:

From the question we are told that

The mass of the left rock is $m_s = 2.25 \ kg$

The mass of the rock on the right $m_p = 10.1 kg$

The distance from fulcrum to the center of the pile of rocks is $r_p = 0.360 \ m$

Generally the torque produced by the pile of rock is mathematically represented as

$\tau = m_p * g * r_p$

Substituting values

$\tau = 10.1 * 9.8 * 0.360$

$\tau = 35.63\ N \cdot m$

Generally we can mathematically evaluated the distance of the the single rock that would put the system in equilibrium as follows

The torque due to the single rock is

$\tau = m_s * g * r_s$

At equilibrium the both torque are equal

$35.63 = m_s * r_s * g$

Making $r_s$ the subject of the formula

$r_s = \frac{35.63 }{m_s * g}$

Substituting values

$r_s = \frac{35.63 }{2.25 * 9.8}$

$r_s =1.62 \ m$

6 0

3 years ago

Ok plz answer and tell me how to do it

kirza4 [7]

Answer: 25N

method: total force in the right hand direction is 100N and total force in the left hand direction is 125N. To get the net force, we add forces if they are in the same direction and substract if they are in opposite directions. since 100N and 125N are in opposite directions, we substract the larger value from the smaller value. Then we get 25N in the left hand direction as the final answer.

4 0

3 years ago