<h2>
<em><u>A</u></em><em><u>N</u></em><em><u>S</u></em><em><u>W</u></em><em><u>E</u></em><em><u>R</u></em><em><u>S</u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em></h2>
<em>1) The relationship in between the electrical energy carriesd by the transmission wires and the amount of the heat loss in it is due to the reason that when the electricity is flown through the wires there are some resistance found in these wires which creates a disturbance in the efficient flow of electricty.Also we know that current have an heating effect when it is in motion as due to if a large amount or magnitude of electricity is flown through the transmission wires it will carry a larger heat effected and also due to the resistance is provided by the wires and so the process of heat loss takes place.</em>
<em>2)It is important to minimize current in transmission wires due to minimize the heat loss and resistance on flowing electric current to make the system more efficient </em>
<em><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u></em><em> 3)Given Resistance = 250 ohms </em>
<em>Electric potential = 150 volts </em>
<em>so we know Power = </em>
<em>volt^2/Resistance = </em>
<em>=</em><em>(150^2/250)(ohms/volts)</em>
<em>=</em><em>(22500/250)watt = 9</em><em>0</em><em> </em><em>w</em><em>a</em><em>t</em><em>t</em><em> </em>
<em>4)Heat energy (H) = Power(P)×Time(t)</em>
<em>4)Heat energy (H) = Power(P)×Time(t)= (90×2)joules = 180 joul</em><em>e</em><em>s</em>
<em>H</em><em>o</em><em>p</em><em>e</em><em> </em><em>i</em><em>t</em><em> </em><em>h</em><em>e</em><em>l</em><em>p</em><em>s</em>
Answer:
"Magnitude of a vector can be zero only if all components of a vector are zero."
Explanation:
"The magnitude of a vector can be smaller than length of one of its components."
Wrong, the magnitude of a vector is at least equal to the length of a component. This is because of the Pythagoras theorem. It can never be smaller.
"Magnitude of a vector is positive if it is directed in +x and negative if is is directed in -X direction."
False. Magnitude of a vector is always positive.
"Magnitude of a vector can be zero if only one of components is zero."
Wrong. For the magnitude of a vector to be zero, all components must be zero.
"If vector A has bigger component along x direction than vector B, it immediately means, the vector A has bigger magnitude than vector B."
Wrong. The magnitude of a vector depends on all components, not only the X component.
"Magnitude of a vector can be zero only if all components of a vector are zero."
True.
Answer:
Explanation:
position of centre of mass of door from surface of water
= 10 + 1.1 / 2
= 10.55 m
Pressure on centre of mass
atmospheric pressure + pressure due to water column
10 ⁵ + hdg
= 10⁵ + 10.55 x 1000 x 9.8
= 2.0339 x 10⁵ Pa
the net force acting on the door (normal to its surface)
= pressure at the centre x area of the door
= .9 x 1.1 x 2.0339 x 10⁵
= 2.01356 x 10⁵ N
pressure centre will be at 10.55 m below the surface.
When the car is filled with air or it is filled with water , in both the cases pressure centre will lie at the centre of the car .
1) Fundamental units of
are ![[\frac{mol}{m\cdot s^2}]](https://tex.z-dn.net/?f=%5B%5Cfrac%7Bmol%7D%7Bm%5Ccdot%20s%5E2%7D%5D)
2) Fundamental units of
are ![[\frac{mol}{m^3}]](https://tex.z-dn.net/?f=%5B%5Cfrac%7Bmol%7D%7Bm%5E3%7D%5D)
Explanation:
The equation for the variable
is

where we have:
measured in ![[\frac{mol}{ft^3}]](https://tex.z-dn.net/?f=%5B%5Cfrac%7Bmol%7D%7Bft%5E3%7D%5D)
measured in ![[\frac{J}{kg}]](https://tex.z-dn.net/?f=%5B%5Cfrac%7BJ%7D%7Bkg%7D%5D)
measured in ![[in]](https://tex.z-dn.net/?f=%5Bin%5D)
measured in ![[\frac{m}{s^2}]](https://tex.z-dn.net/?f=%5B%5Cfrac%7Bm%7D%7Bs%5E2%7D%5D)
We can re-write the equation as

And we notice that the units of the term on the left must be equal to the units of the term on the right.
This means that:
1) First of all,
must have the same units of
. So,
![[\rho r g]=[\frac{mol}{ft^3}][in][\frac{m}{s^2}]](https://tex.z-dn.net/?f=%5B%5Crho%20r%20g%5D%3D%5B%5Cfrac%7Bmol%7D%7Bft%5E3%7D%5D%5Bin%5D%5B%5Cfrac%7Bm%7D%7Bs%5E2%7D%5D)
However, both ft (feet) and in (inches) are not fundamental dimensions: this means that they can be expressed as meters. Therefore, the fundamental units of
are
![[\Psi]=[\frac{mol}{m^3}][m][\frac{m}{s^2}]=[\frac{mol}{m\cdot s^2}]](https://tex.z-dn.net/?f=%5B%5CPsi%5D%3D%5B%5Cfrac%7Bmol%7D%7Bm%5E3%7D%5D%5Bm%5D%5B%5Cfrac%7Bm%7D%7Bs%5E2%7D%5D%3D%5B%5Cfrac%7Bmol%7D%7Bm%5Ccdot%20s%5E2%7D%5D)
2)
The term
must have the same units of
in order to be added to it. Therefore,
![[\gamma \Phi] = [\frac{mol}{m\cdot s^2}]](https://tex.z-dn.net/?f=%5B%5Cgamma%20%5CPhi%5D%20%3D%20%5B%5Cfrac%7Bmol%7D%7Bm%5Ccdot%20s%5E2%7D%5D)
We also know that the units of
are
, therefore
![[\frac{J}{kg}][\Phi]= [\frac{mol}{m\cdot s^2}]](https://tex.z-dn.net/?f=%5B%5Cfrac%7BJ%7D%7Bkg%7D%5D%5B%5CPhi%5D%3D%20%5B%5Cfrac%7Bmol%7D%7Bm%5Ccdot%20s%5E2%7D%5D)
And so, the fundamental units of
are
![[\Phi]= [\frac{mol\cdot kg}{J\cdot m\cdot s^2}]](https://tex.z-dn.net/?f=%5B%5CPhi%5D%3D%20%5B%5Cfrac%7Bmol%5Ccdot%20kg%7D%7BJ%5Ccdot%20m%5Ccdot%20s%5E2%7D%5D)
However, the Joules can be written as
![[J]=[kg][\frac{m^2}{s^2}]](https://tex.z-dn.net/?f=%5BJ%5D%3D%5Bkg%5D%5B%5Cfrac%7Bm%5E2%7D%7Bs%5E2%7D%5D)
Therefore
![[\Phi]= [\frac{mol\cdot kg}{(kg \frac{m^2}{s^2})\cdot m\cdot s^2}]=[\Phi]= [\frac{mol}{m^3}]](https://tex.z-dn.net/?f=%5B%5CPhi%5D%3D%20%5B%5Cfrac%7Bmol%5Ccdot%20kg%7D%7B%28kg%20%5Cfrac%7Bm%5E2%7D%7Bs%5E2%7D%29%5Ccdot%20m%5Ccdot%20s%5E2%7D%5D%3D%5B%5CPhi%5D%3D%20%5B%5Cfrac%7Bmol%7D%7Bm%5E3%7D%5D)
#LearnwithBrainly
Answer:
Both attempt to explain human behavior
Explanation:
Psychology is generally regarded as the science of human behavior. Behaviourism is the psychological theory which holds that behaviour can be fully understood in terms of conditioning, without actually considering thoughts or feelings. The theory holds that psychological disorders can be aptly handled by simply altering the behavioural patterns of the individual. It involves the study of stimulus and responses.
Cognitive psychology attempts to decipher what is going on in people's minds. That is, it looks at the mind as a processor of information. Hence we can define cognitive psychology as the study of the internal mental processes. This according to behaviorists, cannot be studied in measurable terms as in behaviourism (stimulus response approach) even though mental processes are known to influence human behavior significantly.
Hence, both behaviourism and cognitive psychology attempt to study human behavior from different perspectives.