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Sindrei [870]
3 years ago
8

(04.06 LC)

Chemistry
1 answer:
Juliette [100K]3 years ago
5 0

Answer: Either Electrons and nucleus or Protons and neutrons

not sure but im leaning more to electrons and nutreons

Explanation:

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How much heat is gained when a 50.32g piece of aluminum is heated from 9.0°c to 16°c
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Answer: 317 joules

Explanation:

The quantity of heat energy (Q) gained by aluminium depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

In this case,

Q = ?

Mass of aluminium = 50.32g

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Φ = (Final temperature - Initial temperature)

= 16°C - 9°C = 7°C

Then, Q = MCΦ

Q = 50.32g x 0.90J/g°C x 7°C

Q = 317 joules

Thus, 317 joules of heat is gained.

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Just find the energy of the <span>blueviolet light with a wavelength of 434.0 nm using the formula:

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Putting these values (with appropriate units) in the above formula :

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<span>Means the electron will not be removed

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Explanation:

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