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Deffense [45]
3 years ago
9

HEllo i need help with reading how do i read

Chemistry
1 answer:
hram777 [196]3 years ago
5 0
Try to sound out the words ! :)
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What is an acid according to Arrhenius?
MariettaO [177]
Hello there.

<span>What is an acid according to Arrhenius?

</span><span>b. a substance that is a hydrogen ion donor
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3 0
4 years ago
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The difference between the initial (first) position and the final position of an object
Anna [14]
It is called DISPLACEMENT of the object....
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4 years ago
One photon of a certain type of light has an energy of 7.32x10^-19 J. a.) What is the frequency of this type of light? b.) What
iren [92.7K]

Answer:

f = 1.1041 × 10¹⁵ s⁻¹

λ = 2.72  × 10⁻⁷ m

Explanation:

Given data:

Energy of photon = 7.32 × 10⁻¹⁹ J

Wavelength = ?

Frequency = ?

Solution:

Formula

E = h. f

h = planck's constant = 6.63 × 10⁻³⁴ Kg.m²/s

Now we will put the values in equation

f = E/h

Kg.m²/s² = j

f = 7.32 × 10⁻¹⁹ Kg.m²/s² / 6.63 × 10⁻³⁴ Kg.m²/s

f = 1.1041 × 10¹⁵ s⁻¹

Wavelength of photon.

E = h.c /λ

λ =  h. c / E

λ = (6.63 × 10⁻³⁴ Kg.m²/s × 3 × 10⁸ m/s) / 7.32 × 10⁻¹⁹ Kg.m²/s²

λ = 19.89 × 10⁻²⁶ / 7.32 × 10⁻¹⁹ m

λ = 2.72  × 10⁻⁷ m

7 0
3 years ago
How many liters of 1.0 M HCl do you need to neutralize 2.0 L of 3.0 M NaOH? How many liters of 1.0 M HCl do you need to neutrali
Kruka [31]

<u>Answer: </u>

<u>For 1:</u> The volume of HCl required is 6 L.

<u>For 2:</u> The volume of HCl required is 9 L.

<u>For 3:</u> The volume of sulfuric acid required is 4.5 L.

<u>Explanation:</u>

To calculate the volume of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2        ......(1)

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base

  • <u>For 1:</u>

We are given:

n_1=1\\M_1=1M\\V_1=?L\\n_2=1\\M_2=3.0M\\V_2=2.0L

Putting values in equation 1, we get:

1\times 1\times V_1=1\times 3\times 2\\\\V_1=6L

Hence, the volume of HCl required is 6 L.

  • <u>For 2:</u>

We are given:

n_1=1\\M_1=1M\\V_1=?L\\n_2=2\\M_2=3.0M\\V_2=1.5L

Putting values in equation 1, we get:

1\times 1\times V_1=2\times 3.0\times 1.5\\\\V_1=9L

Hence, the volume of HCl required is 9 L.

  • <u>For 3:</u>

To calculate the volume of acid, we use the equation:

N_1V_1=N_2V_2

where,

N_1\text{ and }V_1 are the normality and volume of acid

N_2\text{ and }V_2 are the normality and volume of base

We are given:

N_1=1.0N\\V_1=?L\\N_2=3.0N\\V_2=1.5L

Putting values in above equation, we get:

1.0\times V_1=3.0\times 1.5\\\\V_1=4.5L

Hence, the volume of sulfuric acid required is 4.5 L.

8 0
3 years ago
Which of these following have a positive charges
Over [174]
Talking about ions, a cation has a positive charge. That means a positive charge is gained by an atom that gives out electrons. 
7 0
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