Answer:
The temperature is 298.5 K, which corresponds to 0.50°C.
A jacket would be appropriate clothing for this weather.
Explanation: Hope this helps:)
Answer:
40.02 calories
Explanation:
V = 10 mL = 10g
we know t went <em>up</em> by 4°C, this is our ∆t as it is a change.
Formula that ties it together: Q = mc∆t
where,
Q = energy absorbed by water
m = mass of water
c = specific heat of water (constant)
∆t = temperature change
Q = (10 g) x (4.186 J/g•°C) x (4°C)
Q = 167.44 J
Joules to Calories:
167.44 J x 1 cal/4.184 J = 40.02 calories
(makes sense as in image it is close to the value).
Answer I'm not quite sure if this is right, but maybe it's because Jessica put her thermometer deeper in the stream, and Javier put his more up.
Explanation:
The answer would be more heat