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Contact [7]
3 years ago
13

Rebekah finds that a solution of sugar in water has a volume of 1. 32 fl. Oz. How should she report this amount using the metric

system? (1 fl. Oz. = 29. 6 mL) 0. 403 m 1. 40 qt 37. 5 g 39. 1 mL.
Chemistry
1 answer:
goldfiish [28.3K]3 years ago
4 0

Rebekah reports the volume of sugar solution using metric system as 39.1 mL. Thus, option D is correct.

The metric system has been the measurement system introduced in 1790s. The system has mediated the units for the measurement of volume, mass, length.

The volume has been the space that has been occupied by matter. The volume can be denoted with SI unit L. However, the another accepted unit for volume has been mL.

Thus, the volume of sugar solution has been reported in mL.

The given sugar solution has volume of 1.32 fl. Oz

The volume in mL can be given as:

\rm 1\;fl\;Oz=29.6\;mL\\1.32\;fl\;Oz=1.32\;\times\;29.6\;mL\\1.32\;fl\;Oz=39.1\;mL

The volume of the sugar solution reported by Rebekah on the metric scale has been 39.1 mL. Thus, option D is correct.

For more information about the metric system, refer to the link:

brainly.com/question/25011390

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3. Given 20g of Barium Hydroxide, how many grams of
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The number of grams of ammonium nitrate (NH₄NO₃) it would take for all the barium hydroxide to react is 18.7g

First, we will write the balanced chemical equation for the reaction

The balanced chemical equation for the reaction is

Ba(OH)₂ + 2NH₄NO₃ → 2NH₄OH + Ba(NO₃)₂

This means, 1 mole of barium hydroxide is required to react with 2 moles of ammonium nitrate

Now, we will calculate the number of moles of barium hydroxide present.

Mass of barium hydroxide (Ba(OH)₂) = 20 g

Using the formula

Number\ of\ moles = \frac{Mass}{Molar\ mass}

Molar mass of Ba(OH)₂ = 171.34 g/mol

∴ Number of moles of Ba(OH)₂ present =\frac{20}{171.34}

Number of moles of Ba(OH)₂ present = 0.116727 mole

Now,

Since 1 mole of barium hydroxide is required to react with 2 moles of ammonium nitrate

Then,

0.116727 mole of barium hydroxide will react with 2 × 0.116727 mole of ammonium nitrate

2 × 0.116727 = 0.233454 mole

∴ Number of moles of NH₄NO₃ required is 0.233454 mole

Now, for the mass of ammonium nitrate (NH₄NO₃) required

From the formula

Mass = Number of moles × Molar mass

Molar mass of NH₄NO₃ = 80.043 g/mol

∴ Mass of NH₄NO₃ required = 0.233454 × 80.043

Mass of NH₄NO₃ required = 18.68636 g

Mass of NH₄NO₃ required ≅ 18.7g

Hence, the number of grams of ammonium nitrate (NH₄NO₃) it would take for all the barium hydroxide to react is 18.7g

Learn more on determining mass of reactant required here: brainly.com/question/11232389

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