Rebekah finds that a solution of sugar in water has a volume of 1. 32 fl. Oz. How should she report this amount using the metric
1 answer:
Rebekah reports the volume of sugar solution using metric system as 39.1 mL. Thus, option D is correct.
The metric system has been the measurement system introduced in 1790s. The system has mediated the units for the measurement of volume, mass, length.
The volume has been the space that has been occupied by matter. The volume can be denoted with SI unit L. However, the another accepted unit for volume has been mL.
Thus, the volume of sugar solution has been reported in mL.
The given sugar solution has volume of 1.32 fl. Oz
The volume in mL can be given as:
The volume of the sugar solution reported by Rebekah on the metric scale has been 39.1 mL. Thus, option D is correct.
For more information about the metric system, refer to the link:
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Answer : The value of for the reaction is +571.6 kJ/mole.
Explanation :
According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.
According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.
The given chemical reaction is,
Now we have to determine the value of for the following reaction i.e,
According to the Hess’s law, if we reverse the reaction then the sign of change.
So, the value for the reaction will be:
Hence, the value of for the reaction is +571.6 kJ/mole.
Answer:
The answer to your question is given after the questions so I just explain how to get it.
Explanation:
a)
Get the molecular weight of Phosphoric acid
H₃PO₄ = (3 x 1) + (31 x 1) + (16 x 4)
= 3 + 31 + 64
= 98 g
98 g ----------------- 1 mol
0.045 g --------------- x
x = (0.045 x 1) / 98
x = 0.045 / 98
x = 0.00046 moles or 4.6 x 10 ⁻⁴
b)
Molarity =
Molarity =
Molarity = 0.0013 or 1.31 x 10⁻³
c)
Formula C₁V₁ = C₂V₂
V₁ = C₂V₂ / C₁
Substitution
V₁ = (0.0013)(1) / 0.01
Simplification and result
V₁ = 0.0013 / 0.1
V₁ = 0.13 l = 130 ml