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Vitek1552 [10]
3 years ago
11

What does the quantum mechanical model determine about electrons in atoms

Physics
1 answer:
Brums [2.3K]3 years ago
8 0

The quantum mechanical model determines the allowed energies an electron can have and how likely it is to find the electron in various locations around the nucleus... The energy of electrons in atoms are said to be quantized.

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Why does an object have a different weight on the moon than it does on Earth? Everything is weightless in space. Objects move mo
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From the list of choices, the best one is  "The Earth and moon have
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3 years ago
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Which of these is a good example of Newton's First Law of inertia
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Answer: The correct option is A.

Explanation:

Inertia is a state of an object or body to maintain its state. It resists any change in its state.

Newton's first law of inertia: When an objects is in state of motion, it will remain its state of motion or if it is in state of rest then it will remain in rest unless it is acted upon by external motion.

In the given options, a ball sits motionless on the ground is good example of Newton's first law motion. No external force is acting in this case.

In options (B), (C) and (D) , the external force is acting.

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4 years ago
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Describe the role of observations in scientific endeavor and explain the characteristics of good observations.
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Observations are used in order to collect data and record a variety of interesting or useful key points about the subject or specimen in observation. These observations, if made well, can be recorded and used to supplement a hypothesis. 
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3 years ago
Willing to give out Brainliest: 3.00 m^3 of water is at 20.0°C If you raise its temperature to 60.0°C, by how much will its volu
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Answer:

The answer is below

Explanation:

Charlee's law states that the volume of a gas is directly proportion to the temperature of the gas at constant pressure. That is:

V = kT, where V = volume and T = temperature, k = constant. Therefore:

V / T = k

\frac{V_1}{T_1}=\frac{V_2}{T_2}

Given that: V_1=3\ m^3, T_1=20^oC=(20 + 273)K=293\ k,T_2=60^oC=(60 + 273)K=333\ k.\\\\\frac{V_1}{T_1}=\frac{V_2}{T_2}\\\\\frac{3}{293}=\frac{V_2}{333}    \\\\V_2=\frac{3}{293}*333\\\\V_2=3.41\ m^3\\

The new volume is 3.41 m³. That is it expands by 0.41 m³

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